如何在PHP中回显已准备好的sql语句的结果

Posted 2023-01-12

我正在尝试使用准备好的语句从数据库中回显数据。我被困在实际循环显示结果上]

这里是代码：

$sql = "select fname,lname,email,address,suburb,state,postcode,phone from customer where id = ? ";
  $stmt = $dbConn->prepare($sql);
  $stmt->bind_param("s", $user);
  $Stmt->execute();
  $rs = $stmt->get_result();

<?php while($row = $stmt->fetch_assoc())  ?>

    <h3> Your Current Details: </h3>
    <p><strong>first name:</strong> <?php  echo $row['fname'] ; ?></p>
    <p><strong>last name:</strong> <?php echo $row['lname'] ; ?></p>
    <p><strong>email:</strong> <?php echo $row['email'] ; ?></p>
    <p><strong>post code:</strong> <?php echo $row['postcode'] ;?></p>
    <p><strong>state:</strong> <?php echo $row ['state'] ; ?></p>
    <p><strong>address:</strong> <?php echo $row ['address'] ; ?></p>
    <p><strong>suburb:</strong> <?php echo $row ['suburb'] ;?></p>
    <p><strong>phone:</strong> <?php echo $row ['phone'] ; ?></p>
    </div> 

我不熟悉使用预备陈述，使用预备陈述时，所有类似的帖子和在线帖子都显示了不同的方法。 （他们使用PDO）

答案

也许尝试这样的事情：

$sql = "select fname,lname,email,address,suburb,state,postcode,phone from customer where id = ? ";
$stmt = $dbConn->prepare($sql);
$stmt->bind_param("s", $user);
$stmt->execute();
$rs = $stmt->get_result();

echo "<h3> Your Current Details: </h3>";
while ($row = $stmt->fetch_assoc()) 
    echo "<p><strong>first name:</strong>" . $row['fname'] . "</p>";
    echo "<p><strong>last name:</strong>" . $row['lname'] . "</p>";
    echo "<p><strong>email:</strong>" . $row['email'] . "</p>";
    echo "<p><strong>post code:</strong>" . $row['postcode'] . "</p>";
    echo "<p><strong>state:</strong>" . $row ['state'] . "</p>";
    echo "<p><strong>address:</strong>" . $row ['address'] . "</p>";
    echo "<p><strong>suburb:</strong>" . $row ['suburb'] . "</p>";
    echo "<p><strong>phone:</strong>" . $row ['phone'] . "</p>";

echo "</div>";