Python Selenium-使用YouTube调试简单代码

Posted 2023-01-11

我遵循了有关Python的Selenium的本教程：https://www.youtube.com/watch?v=f7LEWxX4AVI&list=PLPIqsJye1aPybIwQ1L47gY36lkQ6yL975&index=3&t=397s

所以我做的和本教程一样：

from selenium import webdriver

driver=webdriver.Chrome()
driver.get('https://www.youtube.com/')

searchbox = driver.find_element_by_xpath('//*[@id="search-input"]')
searchbox.send_keys('cooking')

但我收到此错误：

Traceback (most recent call last):
  File "C:/ANGUS/DATA_ANALYSIS/WEBSCRAPING/TextXXX.py", line 7, in <module>
    searchbox.send_keys('cooking')
  File "C:\Users\Angus\PycharmProjects\Test\venv\lib\site-packages\selenium\webdriver\remote\webelement.py", line 477, in send_keys
    self._execute(Command.SEND_KEYS_TO_ELEMENT,
  File "C:\Users\Angus\PycharmProjects\Test\venv\lib\site-packages\selenium\webdriver\remote\webelement.py", line 633, in _execute
    return self._parent.execute(command, params)
  File "C:\Users\Angus\PycharmProjects\Test\venv\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 321, in execute
    self.error_handler.check_response(response)
  File "C:\Users\Angus\PycharmProjects\Test\venv\lib\site-packages\selenium\webdriver\remote\errorhandler.py", line 242, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.ElementNotInteractableException: Message: element not interactable
  (Session info: chrome=81.0.4044.138)

只是想不通，所以在此先谢谢您的帮助。

答案

为了避免使用搜索的另一种方法是插入查询本身。检查：

CODE

your_query = "cooking"

driver.get("https://www.youtube.com/results?search_query=" + str(your_query))

time.sleep(5)

这样，就好像您在搜索特定查询后立即进入所需的输出。因此，我们可以说，不用键入烹饪，而是可以通过将查询添加到所需的URL来将.get（）添加到该URL。

我希望这对您有所帮助：）