Exception：无法静态引用非静态字段播放器

Posted 2023-01-09

我正在用Java编写程序来注册播放器并将它们添加到arraylist中。我添加玩家的方法是：

void registerNewPlayer() 
        System.out.print("Name?> ");
        String name = input.nextLine();
        System.out.print("Game?> ");
        String game = input.nextLine();
        System.out.print("Age?> ");
        int age = input.nextInt();
        Player player = new Player(name, game, age);
        players.add(player);
    

我的问题是我不知道该放在哪里

 ArrayList<Player> players = new ArrayList<>();

如果我主要拥有该方法，则该方法不知道玩家是什么，但是如果我在课堂上拥有它，当我尝试从主打印。解决此问题的最佳方法是什么。

更新：感谢您的帮助，我意识到，由于我的命令循环已经在类的实例版本上运行，因此实际上没有问题，当我尝试在实例命令循环之外测试我的方法时，只有一个问题。

答案

public class YourClass ArrayList<Player> players = new ArrayList<>(); public static void main(String[] args) new YourClass(); // or YourClass yourClass = new YourClass(); // Create an instance of YourClass to leave the static context public YourClass() registerNewPlayer(); public void registerNewPlayer() System.out.print("Name?> "); String name = input.nextLine(); System.out.print("Game?> "); String game = input.nextLine(); System.out.print("Age?> "); int age = input.nextInt(); System.out.print("Weight?> "); int weight = input.nextInt(); Player player = new Player(name, game, age, weight); players.add(player);

另一答案

您的玩家职业：

1. public class Player private static ArrayList<Player> _players = new ArrayList<Player>(); private String name; private String game; private int age; private int weight; public Player(String name, String game, int age, int weight) this.name = name; this.game = game; this.age = age; this.weight = weight; public static void AddPlayer(Player player) _players.add(player); public static ArrayList<Player> getPlayers() return _players;

   ---

   现在您可以创建一些播放器，并按照以下步骤获取它们：

2. ... main ... . . . Player p1 = new Player("Name1", "Game1", 20, 70); Player p2 = new Player("Name2", "Game2", 30, 80); Player p3 = new Player("Name2", "Game3", 25, 73); Player.AddPlayer(p1); Player.AddPlayer(p2); Player.AddPlayer(p3); ArrayList<Player> allPlayers = Player.getPlayers(); . . .

   ---

   让我知道它是否对您有用！

另一答案

ArrayList<Player> players = new ArrayList<>();