将值插入继承表sql

Posted 2023-01-08

CREATE TABLE projeto.Person(
    Person_Code     INT IDENTITY(1,1)   NOT NULL,
    birthDate           DATE                NOT NULL,
    Name                VARCHAR(50)         NOT NULL,
    PRIMARY KEY(Person_Code)
)

CREATE TABLE projeto.Student (
    Student_Code        INT REFERENCES projeto.Person(Person_Code),
    payment             INT NOT NULL,
    PRIMARY KEY(Student_Code),
)
CREATE TABLE projeto.teacher (
    payment             INT         NOT NULL,
    teacher_Code        INT,
    PRIMARY KEY(teacher_Code),
    CHECK(payment> 350)
)

我如何在学生中插入价值观，注意学生具有所有人的属性？例如学生有名字，生日...

我尝试过：

INSERT INTO projeto.Person VALUES 
    ('1961-03-26', John Adam')

但是这会增加我的面容，我无法确定您是否是学生。

答案

我想它如何获取您正在询问的最近插入的ID？在这种情况下，请使用scope_identity()。

declare @BirthDate date, @Name varchar(50), @Payment int, @IsStudent bit, @IsTeacher bit, @NewId int;

-- SET THE RELEVANT VARIABLE VALUES

-- Insert person
insert into projeto.Person (BirthDate, [Name])
  select @BirthDate, @Name;

-- Get ID of person record
set @NewId = scope_identity();

-- Insert Student record if a student
insert into projeto.Student (Student_Code, Payment)
  select @NewId, @Payment
  where @IsStudent = 1;

-- Insert Teacher record if a teacher
insert into projeto.Teacher (Teacher_Code, Payment)
  select @NewId, @Payment
  where @IsTeacher = 1;