如何根据第三列绘制具有不同颜色的线图？（KeyError：0）

Question

我有一个数据框

                       Company Id   ON/OFF  Level of Fuel
DateTime                            
2018-08-18 00:00:10     25750275    1        82.048     
2018-08-18 00:00:39     25750275    1        82.048     
2018-08-18 00:01:09     25750275    1        79.936     
2018-08-18 00:01:39     25750275    1        79.600     
2018-08-18 00:02:10     25750275    1        78.480

[我想要的是在x轴上具有DateTime索引，在y轴上具有“公司ID”的线图，并且该线应根据[ON？OFF]列中的值[0,1 ]。

从seaborn documentation，我尝试调用以下函数

sns.catplot(x=data.index, y="Level of Fuel", hue="ON/OFF",
            palette="ON": 1, "OFF": 0,
            markers=["^", "o"], linestyles=["-", "--"],
            kind="point",data=data)

但是我得到的KeyError:0的踪迹如下

KeyError                                  Traceback (most recent call last)
<ipython-input-91-cf07ea2f9cbf> in <module>
      2             palette="ON": 1, "OFF": 0,
      3             markers=["^", "o"], linestyles=["-", "--"],
----> 4             kind="point",data=data)

~/.local/lib/python3.6/site-packages/seaborn/categorical.py in catplot(x, y, hue, data, row, col, col_wrap, estimator, ci, n_boot, units, seed, order, hue_order, row_order, col_order, kind, height, aspect, orient, color, palette, legend, legend_out, sharex, sharey, margin_titles, facet_kws, **kwargs)
   3729     # so we need to define ``palette`` to get default behavior for the
   3730     # categorical functions
-> 3731     p.establish_colors(color, palette, 1)
   3732     if kind != "point" or hue is not None:
   3733         palette = p.colors

~/.local/lib/python3.6/site-packages/seaborn/categorical.py in establish_colors(self, color, palette, saturation)
    301                 else:
    302                     levels = self.hue_names
--> 303                 palette = [palette[l] for l in levels]
    304 
    305             colors = color_palette(palette, n_colors)

~/.local/lib/python3.6/site-packages/seaborn/categorical.py in <listcomp>(.0)
    301                 else:
    302                     levels = self.hue_names
--> 303                 palette = [palette[l] for l in levels]
    304 
    305             colors = color_palette(palette, n_colors)

KeyError: 0

如何根据第三列绘制具有不同颜色的线图？ （KeyError：0）

如何根据第三列绘制具有不同颜色的线图？（KeyError：0）