根据与SQL中其他表的重合，来自同一字段的合并行？

Posted 2023-01-07

我尝试从表caracter上载字段t1时遇到问题。如果要在caracter的frase中显示该值，请与前一个值合并。例如，如果在t2中找到x，y或z，并且这些值出现在caracter的frase中，则我想将x，y和z与t2中的上一个值合并。

t1

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t2

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这应该是结果

t1

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我尝试了一个游标，但由于我在set处引用错误，因此无法正常工作，以前我尝试了while循环，但结果相同。

caracter
我在尝试从表t1上传田野角色时遇到问题。我想从caracter中获取该值，如果它在t2的frase中出现，则为先前的值。例如，如果找到x，y或...

希望这达到目的，您必须利用lead（）聚合函数来获取下一行。您可以在带有表和记录的dbfiddle链接中找到完整的解决方案，以显示查询的工作方式。该解决方案适用于SQLSEVER 2019。 DECLARE @frase VARCHAR (100) DECLARE MICURSOR CURSOR FOR SELECT caracter FROM t1 OPEN MICURSOR FETCH NEXT FROM MICURSOR WHILE @@fetch_status = 0 BEGIN SELECT t1.caracter FROM t1 INNER JOIN t2 ON t2.frase LIKE CONCAT('%', t1.caracter,'%') UPDATE t1 SET caracter= 'caracter' + '(@frase-1)' FETCH NEXT FROM MICURSOR INTO @frase END CLOSE MICURSOR DEALLOCATE MICURSOR

https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=71510d727bb04478383887e2e8ab3a52
应用脚本后的输出，

update t1 set t1.caracter = concat(t1.caracter,lg)
from
 (select id_val,ver,caracter,lead(caracter) over (order by id_val) lg from t1) tab,t1
 where lg in (select frase from t2)
 and tab.caracter = t1.caracter;

 delete from t1 where caracter in (select frase from t2);

select * from t1;

id_val  ver caracter
1   abc abc
1   abc 3
1   abc x
1   abc 2
1   abc y
2   def def
2   def 5
2   def y
2   def 9
2   def z

答案

希望这达到目的，您必须利用lead（）聚合函数来获取下一行。您可以在带有表和记录的dbfiddle链接中找到完整的解决方案，以显示查询的工作方式。该解决方案适用于SQLSEVER 2019。 DECLARE @frase VARCHAR (100) DECLARE MICURSOR CURSOR FOR SELECT caracter FROM t1 OPEN MICURSOR FETCH NEXT FROM MICURSOR WHILE @@fetch_status = 0 BEGIN SELECT t1.caracter FROM t1 INNER JOIN t2 ON t2.frase LIKE CONCAT('%', t1.caracter,'%') UPDATE t1 SET caracter= 'caracter' + '(@frase-1)' FETCH NEXT FROM MICURSOR INTO @frase END CLOSE MICURSOR DEALLOCATE MICURSOR