我在存储过程sql中使用CASE条件对中间首字母进行分割双字符

Posted 2023-01-06

例如：代替Juan Juan Dela Cruz Eugenio成为Juan DC。欧金尼奥

SELECT
    (
        UPPER(lastName) 
        + ', '
        +UPPER(SUBSTRING(firstName,1,1)) + LOWER(SUBSTRING(firstName,2,99))
        +' '
        +Suffix
        +' '
        +(
            case
                when tb_persons.middleName = '' or tb_persons.middleName = ' ' or tb_persons.middleName is null
                then ''
                else
                UPPER(SUBSTRING(tb_persons.middleName,1,1))+'.'
            end)
    ) as name,
    UPPER(SUBSTRING(firstName,1,1)) + LOWER(SUBSTRING(firstName,2,99)) as 'firstName',
    UPPER(lastName) as 'lastName',middleName

FROM tb_persons

答案

方法1：
• SELECT CONCAT( PARSENAME(REPLACE(Name, ' ', '.'), 4), ' ', SUBSTRING(PARSENAME(REPLACE(Name, ' ', '.'), 3), 1, 1), SUBSTRING(PARSENAME(REPLACE(Name, ' ', '.'), 2), 1, 1), '.', PARSENAME(REPLACE(Name, ' ', '.'), 1) ) FROM ( VALUES ('Juan Dela Cruz Eugenio') ) T(Name)