使用大写字母在同一行中列出多个日期

Posted 2021-04-07

我正在查询将来的听证会日期。是否可以在聆讯1的同一行中列出第二个聆讯日期-而不是将案件2的行列出。

这里是一个例子：

基本上我不希望第一条记录，我只希望第二条记录都在同一行中。

这是该部分的代码。

SELECT * 
INTO #EventStatusInfoFinal 
FROM ( 
SELECT DISTINCT ESI1.*,
(CASE WHEN ESI1.NextHearingDate = ESI2.NextHearingDate THEN ESI1.NextHearingDate
    ELSE ESI1.NextHearingDate
END) AS 'NextHearingDate1',
(CASE WHEN ESI1.NextHearingDate != ESI2.NextHearingDate THEN ESI2.NextHearingDate
    ELSE ''
END) AS 'NextHearingDate2',
RANK () OVER (PARTITION BY ESI1.CaseID ORDER BY ESI1.NextHearingDate ASC) AS RANK3
FROM #EventStatusInfo ESI1
INNER JOIN #EventStatusInfo ESI2 ON ESI2.CaseID = ESI1.CaseID
) AS X
WHERE X.RANK3 = 1

答案

您可以尝试使用聚合-

SELECT * 
INTO #EventStatusInfoFinal 
FROM ( 
SELECT DISTINCT ESI1.CaseID ,
max(CASE WHEN ESI1.NextHearingDate = ESI2.NextHearingDate THEN ESI1.NextHearingDate
    ELSE ESI1.NextHearingDate
END) AS 'NextHearingDate1',
max(CASE WHEN ESI1.NextHearingDate != ESI2.NextHearingDate THEN ESI2.NextHearingDate
    ELSE null
END) AS 'NextHearingDate2',
RANK () OVER (PARTITION BY ESI1.CaseID ORDER BY ESI1.NextHearingDate ASC) AS RANK3
FROM #EventStatusInfo ESI1
INNER JOIN #EventStatusInfo ESI2 ON ESI2.CaseID = ESI1.CaseID
group by ESI1.CaseID
) AS X
WHERE X.RANK3 = 1

另一答案

这是删除不需要的行的一种简单方法：

SELECT *
FROM (
SELECT DISTINCT ESI1.*,
(CASE WHEN ESI1.NextHearingDate = ESI2.NextHearingDate THEN ESI1.NextHearingDate
ELSE ESI1.NextHearingDate
END) AS 'NextHearingDate1',
(CASE WHEN ESI1.NextHearingDate != ESI2.NextHearingDate THEN ESI2.NextHearingDate
ELSE NULL
END) AS 'NextHearingDate2',
RANK () OVER (PARTITION BY ESI1.CaseID ORDER BY ESI1.NextHearingDate ASC) AS RANK3
FROM EventStatusInfo ESI1
INNER JOIN EventStatusInfo ESI2 ON ESI2.CaseID = ESI1.CaseID
) AS X
WHERE X.RANK3 = 1
and NextHearingDate2 is not null --this is the part I added. 

但是如果您向我们提供您正在使用的表中的示例数据，那么也许我们可以为您提供更好的代码。在此之前，我希望这会对您有所帮助。