如何比较两个目录并获取丢失的文件？ c＃winform

Posted 2021-04-10

这是代码：

enter code here 

private void button1_Click(object sender, EventArgs e)
    {
        try
        {
            string[] Folder1 = Directory.GetFiles(txtFolder1.Text, comboBox1.SelectedItem.ToString());
            string[] Folder1FileNames = new string[Folder1.Length];
            int c = 0;
            string fname1;


            foreach (string f in Folder1)
            {
                fname1 = Path.GetFileName(f);
                Folder1FileNames[c] = fname1;

                c++;
            }



            string fname2;
            string[] Folder2 = Directory.GetFiles(txtFolder2.Text, comboBox1.SelectedItem.ToString());
            string[] Folder2FileNames = new string[Folder2.Length];
            int t = 0;
            foreach (string f in Folder2)
            {
                fname2 = Path.GetFileName(f);
                Folder2FileNames[t] = fname2;
                t++;

            }
            int m=0;
            foreach (string f in Folder1FileNames)
            {
                while (f != Folder2FileNames[m] && m < Folder2FileNames.Length)
                {
                    m++;
                    if (m == Folder2FileNames.Length)
                    {
                        Label newlabe = new Label();
                        newlabe.Text = f;
                        if(!listBox1.Items.Contains(newlabe.Text))
                        {
                            listBox1.Items.Add(newlabe.Text);

                        }
                    }
                }
                m = 0;
            }



        }
        catch (Exception ex)
        {
            label1.Text = ex.Message;
        }

我创建了两个包含Files From SourceDirectory（Folder1）和CompareDirectory（Folder2）的数组，然后更多2个包含文件名的数组，不包括完整的ptah（为了比较araays），然后我试图比较数组，并将缺少的文件添加到列表框中。问题是当我尝试它时它给了我源文件夹中第一个丢失的文件，（例如源文件夹包含下一个文件：a.txt，b.txt，c.txt，d.txt和compare文件夹包含：a .txt，b.txt，列表框中的结果将是c.txt，标签将显示：“你是不在数组索引中”）我该怎么办？谢谢！

答案

您可以使用更简单，更整洁的解决方案，类似的应该可以工作：

var dir1Files = Directory
    .EnumerateFiles(txtFolder1.Text, "*", SearchOption.AllDirectories)
    .Select(Path.GetFileName);
var dir2Files = Directory
    .EnumerateFiles(txtFolder2.Text, "*", SearchOption.AllDirectories)
    .Select(Path.GetFileName);
var diffs = dir1Files.Except(dir2Files).Distinct().ToArray();   

listBox1.Items.AddRange(diffs);

另一答案

谢谢你们，我成功地按照自己的方式去做了。多数民众赞成我的旧代码：

int m=0;
        foreach (string f in Folder1FileNames)
        {
            while (f != Folder2FileNames[m] && m < Folder2FileNames.Length)
            {
                m++;
                if (m == Folder2FileNames.Length)
                {
                    Label newlabe = new Label();
                    newlabe.Text = f;
                    if(!listBox1.Items.Contains(newlabe.Text))
                    {
                        listBox1.Items.Add(newlabe.Text);

                    }
                }
            }
            m = 0;
        }

新的是：`

 int m = 0;
            foreach (string f in Folder1FileNames)
            {
                m = 0;
                while (f != Folder2FileNames[m] && m < Folder2FileNames.Length-1)
                {
                    m++;
                    if (m == Folder2FileNames.Length-1)
                    {
                        if (Folder2FileNames[m] != f)
                        {

                            Label newlabe = new Label();
                            newlabe.Text = f;
                            if (!listBox1.Items.Contains(newlabe.Text))
                            {
                                listBox1.Items.Add(newlabe.Text);

                            }
                        }


                    }
                }

            }

现在它运行良好，这样我就不会超出数组索引了

另一答案

    // Find the set difference between the two folders.  
    // For this example we only check one way.  
    var queryList1Only = (from file in list1  
                          select file).Except(list2, myFileCompare);  

    Console.WriteLine("The following files are in list1 but not list2:");  
    foreach (var v in queryList1Only)  
    {  
        Console.WriteLine(v.FullName);  
    }  

See full example