如何创建具有多个菜单的pygame？

Posted 2021-04-18

如果我点击第一个菜单上的播放按钮，它应该打开一个菜单供用户选择级别。在我写的代码中，单击播放按钮，计算机也假设我也点击了与水平屏幕中的播放按钮放在同一位置的简易按钮。它直接进入游戏循环。

答案

可能你使用mouse.get_pressed()，当按住按钮时它会给True - 这会产生问题。使用事件MOUSEBUTTONDOWN只有当按钮从"not-pressed"变为"pressed"时才会得到“True”，但是当按住它时不会。

但大多数情况下，按钮需要进行大量更改，尤其是在一个功能中有按钮的情况下。

使用类Button的示例

import pygame

# --- constants ---

WIDTH = 320
HEIGHT = 110

FPS = 5

# --- class ---

class Button(object):

    def __init__(self, position, size, color, text):

        self.image = pygame.Surface(size)
        self.image.fill(color)
        self.rect = pygame.Rect((0,0), size)

        font = pygame.font.SysFont(None, 32)
        text = font.render(text, True, (0,0,0))
        text_rect = text.get_rect()
        text_rect.center = self.rect.center

        self.image.blit(text, text_rect)

        # set after centering text
        self.rect.topleft = position

    def draw(self, screen):
        screen.blit(self.image, self.rect)

    def is_clicked(self, event):
        if event.type == pygame.MOUSEBUTTONDOWN:
            if event.button == 1:
                return self.rect.collidepoint(event.pos)

def stage1(screen):

    button1 = Button((5, 5), (100, 100), (0,255,0), "GO 1")
    button2 = Button((215, 5), (100, 100), (0,255,0), "EXIT")

    # - mainloop -

    clock = pygame.time.Clock()
    running = True

    while running:

        # - events -

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                exit()
            elif event.type == pygame.KEYDOWN:
                if event.key == pygame.K_ESCAPE:
                    pygame.quit()

            if button1.is_clicked(event):
                # go to stage2
                stage2(screen)
            if button2.is_clicked(event):
                # exit
                pygame.quit()
                exit()

        # - draws -

        screen.fill((255,0,0))    
        button1.draw(screen)
        button2.draw(screen)
        pygame.display.flip()

        # - FPS -

        clock.tick(FPS)

def stage2(screen):

    button1 = Button((5, 5), (100, 100), (255,0,0), "GO 2")
    button2 = Button((215, 5), (100, 100), (255,0,0), "BACK")

    # - mainloop -

    clock = pygame.time.Clock()
    running = True

    while running:

        # - events -

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                exit()
            elif event.type == pygame.KEYDOWN:
                if event.key == pygame.K_ESCAPE:
                    pygame.quit()

            if button1.is_clicked(event):
                stage3(screen)
            if button2.is_clicked(event):
                return

        # - draws -

        screen.fill((0,255,0))    
        button1.draw(screen)
        button2.draw(screen)
        pygame.display.flip()

        # - FPS -

        clock.tick(FPS)

def stage3(screen):

    button2 = Button((215, 5), (100, 100), (0,0,255), "BACK")

    # - mainloop -

    clock = pygame.time.Clock()
    running = True

    while running:

        # - events -

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                exit()
            elif event.type == pygame.KEYDOWN:
                if event.key == pygame.K_ESCAPE:
                    pygame.quit()

            if button2.is_clicked(event):
                return

        # - draws -

        screen.fill((128,128,128))    
        button2.draw(screen)
        pygame.display.flip()

        # - FPS -

        clock.tick(FPS)

# --- main ---

# - init -

pygame.init()

screen = pygame.display.set_mode((WIDTH, HEIGHT))

# - start -

stage1(screen)

# - end -

pygame.quit()