我的SQL查询正在处理一个日期，但我希望开始日期到结束日期
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我正在使用SQL Server 2005
我有两张桌子：
CheckInOut
TR BadgeNum USERID Dated Time CHECKTYPE
------- --------- ------ ----------------------- ----------------------- ----------
2337334 4 1 2018-04-01 00:00:00.000 2018-04-14 10:10:58.000 I
2337334 4 1 2018-04-01 00:00:00.000 2018-04-14 18:10:00.000 O
2337334 4 1 2018-04-02 00:00:00.000 2018-04-14 10:00:10.000 I
2337335 4 1 2018-04-02 00:00:00.000 2018-04-14 18:14:27.000 O
2337336 4 1 2018-04-03 00:00:00.000 2018-04-14 10:22:10.000 I
2337334 4 1 2018-04-03 00:00:00.000 2018-04-14 18:03:11.000 O
2337337 44 5 2018-04-01 00:00:00.000 2018-04-14 09:27:03.000 I
2337337 44 5 2018-04-01 00:00:00.000 2018-04-14 18:27:42.000 O
2337337 44 5 2018-04-02 00:00:00.000 2018-04-14 10:00:50.000 I
2337337 44 5 2018-04-02 00:00:00.000 2018-04-14 18:02:25.000 O
2337337 44 5 2018-04-03 00:00:00.000 2018-04-14 08:58:36.000 I
2337337 44 5 2018-04-03 00:00:00.000 2018-04-14 18:12:18.000 O
用户信息
Tr UserID BadgeNumber Name
----- ------- ----------- --------------
13652 44 5 SAMIA NAZ
13653 4 1 Waqar Yousufzai
我需要为每个用户计算每天的存在时间。我的下面的查询在给定的一天工作正常。但我需要计算给定的范围。我如何得到预期的结果？
Select isnull(max(ch.userid), 0)As 'ID'
,isnull(max(ch.badgenum), 0)as 'Badge#'
,isnull(max(convert(Char(10), ch.dated, 103)), '00:00')as 'Date'
,isnull(max(ui.name),'Empty')as 'Name'
,isnull(min(convert(VARCHAR(26), ch.time, 108)), '00:00') as 'Time In'
,case when min(ch.time) = max(ch.time) then '' else isnull(max(convert(VARCHAR(26), ch.time, 108)), '00:00') end as 'TimeOut'
,case when min(ch.time) = max(ch.time) then 'Absent' else 'Present' end as 'Status'
,isnull(CONVERT(varchar(3),DATEDIFF(minute,min(ch.time), max(ch.time))/60) + ' hrs and ' +
RIGHT('0' + CONVERT(varchar(2),DATEDIFF(minute,min(ch.time),max(ch.time))%60),2) + 'Min' , 0) as 'Total Hrs'
From CHECKINOUT ch left Join userinfo ui on ch.badgenum = ui.badgenumber
Where ch.Dated between '2018-04-01' and '2018-04-03' GROUP BY ch.badgenum
查询结果
ID Badge# Date Name Time In TimeOut Status Total Hrs
--- ------ ---------- --------------- -------- ---------- -------- -----------------
4 1 03/04/2018 Waqar Yousufzai 11:33:34 18:24:23 Present 30 hrs and 14Min
82 3 03/04/2018 TANVEER ANSARI 09:37:14 19:18:22 Present 32 hrs and 37Min
13 4 03/04/2018 07:19:26 09:30:17 Present 21 hrs and 49Min
44 5 03/04/2018 SAMIA NAZ 08:53:15 18:25:21 Present 33 hrs and 24Min
28 7 03/04/2018 Anees Ahmad 08:34:57 22:00:38 Present 61 hrs and 25Min
46 8 03/04/2018 Shazia - OT 08:10:41 16:15:05 Present 32 hrs and 01Min
预期结果
ID Badge# Date Name Time In TimeOut Status Total Hrs
--- ------ ---------- --------------- -------- ---------- -------- -----------------
4 1 01/04/2018 Waqar Yousufzai 10:30:00 18:00:00 Present 7 hrs and 30Min
4 1 02/04/2018 Waqar Yousufzai 10:30:00 18:00:00 Present 7 hrs and 30Min
4 1 03/04/2018 Waqar Yousufzai 10:00:00 18:00:00 Present 8 hrs and 00Min
44 5 01/04/2018 SAMIA 08:00:00 18:00:00 Present 10 hrs and 00Min
44 5 02/04/2018 SAMIA 08:30:00 18:00:00 Present 9 hrs and 30Min
44 5 03/04/2018 SAMIA 08:00:00 18:00:00 Present 10 hrs and 00Min
答案
您不应该对日期值进行聚合，它必须是分组的一部分。使用条件聚合获得时间和时间。并统计工作总时数。您的查询应该是这样的：
select
BadgeNum, USERID, Dated, Name
, right('0' + cast(datediff(mi, [in], [out]) / 60 as varchar(10)), 2) + ':'
+ right('0' + cast(datediff(mi, [in], [out]) % 60 as varchar(10)), 2)
from (
select
ch.BadgeNum, ch.USERID, dated = cast(ch.Dated as date), ui.Name
, [in] = min(case when ch.CHECKTYPE = 'I' then ch.Time end)
, [out] = min(case when ch.CHECKTYPE = 'O' then ch.Time end)
from
CheckInOut ch
left join UserInfo ui on ch.USERID = ui.badgenumber
where
ch.Dated >= '20180401'
and ch.Dated < '20180404'
group by ch.BadgeNum, ch.USERID, cast(ch.Dated as date), ui.Name
) t
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