L1-006. 连续因子

Posted 2020-08-07 code666

#include <iostream>
using namespace std;
#include <cmath>
int main()
{
 int n, t, i, j;
 int num;
 int s;
 cin >> n;
 t = n;
 num = 0, s = 0;
 for (i = 2; i <= sqrt(n) + 1; i++)
 if (n%i == 0)
 {
  t = n / i;
  for (j = i + 1; j <= sqrt(n) + 1; j++)
  if (t%j == 0)  t = t / j;
  else break;
  if (j - i>num) num = j - i, s = i;
 }
 if (num == 0) { num = 1; s = n; }
 cout << num << endl;
 cout << s;
 for (int i = s + 1; i <= s + num - 1; i++)
  cout << "*" << i;
 cout << endl;
 return 0;
}