Es6 之for of

Posted 2020-08-06 云の旋律

 

 

能工摹形，巧匠窃意。 -- 毕加索

 

let nicknames = [‘di‘, ‘boo‘, ‘punkeye‘];
nicknames.size = 3;
for (let nickname of nicknames) {
  console.log(nickname);
}
Result: di, boo, punkeye
for...in 用来遍历对象中的属性：


let nicknames = [‘di‘, ‘boo‘, ‘punkeye‘];
nicknames.size = 3;
for (let nickname in nicknames) {
  console.log(nickname);
}
Result: 0, 1, 2, size

 

 

对比方可以看到这一微弱的变化 所引发的美感！

let nicknames = [‘di‘, ‘boo‘, ‘punkeye‘];
nicknames.size = 3;
for (let nickname of nicknames) {
  console.log(nickname);
}
Result: di, boo, punkeye
for...in 用来遍历对象中的属性：

let nicknames = [‘di‘, ‘boo‘, ‘punkeye‘];
nicknames.size = 3;
for (let nickname in nicknames) {
  console.log(nicknames[nickname]);
}
Result:di, boo, punkeye 3