python搜索替换n个非嵌套组的匹配

Posted 2021-02-27

import re
 
 
def replace(match, withwhat):
 
    starttext = match.group(0)
    n = len(withwhat)
    off = match.start(0)
 
    tmp = starttext
    for i in range(n):
            delta = len(tmp)-len(starttext)
            tmp = tmp[:match.start(i+1)-off+delta ] + withwhat[i](match.group(i+1)) + tmp[match.end(i+1)-off+delta:]
    return tmp
 
#test
funcs = [lambda x: '1'+x+'1',lambda x: '2'+x+'2']
#regex contains 2 capturing groups
print re.sub(regex, lambda x: replace(x, funcs), text)