多个循环计数器公用cx的解决办法

Posted 2020-08-06 ynov

简单 ，提前cx入栈

assume cs:codesg,ds:datssg,ss:stacksg

datasg segment
   db ‘ibm             ‘
   db ‘dec             ‘
   db ‘dos             ‘
   db ‘vax             ‘
data ends

stack segment
   dw 0,0,0,0,0,0,0,0
stack ends

codesg segment

   start:mov ax,stacksg
           mov ss,ax
           mov sp,16
           mov ax,datasg
           mov ds,ax
           mov bx,0

           mov cx,4
   
 
   s0:     push cx
           mov si,0
           mov cx,3

   s:      mov al,[bx+si]
           and al,11011111b
           mov [bx+si],al
           inc si
           loop s

           add bx,16
           pop cx
           loop s0

           mov ax,4c00H
           int 21H

codesg ends
end start

 

用的时候直接出来完事，随用随建栈233