Codeforces Round #260 (Div. 2) A

Posted 2020-08-06 樱花落舞

Description

One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality of the first laptop is higher (strictly greater) than the quality of the second laptop.

Please, check the guess of Alex. You are given descriptions of n laptops. Determine whether two described above laptops exist.

Input

The first line contains an integer n (1 ≤ n ≤ 105) — the number of laptops.

Next n lines contain two integers each, ai and bi (1 ≤ ai, bi ≤ n), where ai is the price of the i-th laptop, and bi is the number that represents the quality of the i-th laptop (the larger the number is, the higher is the quality).

All ai are distinct. All bi are distinct.

Output

If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes).

Examples

input

2
1 2
2 1

output

Happy Alex
题意：问你是价格高才质量高，还是价格低质量高
解法：排序，如果发现价格高但质量比之前的低，就输出Poor Alex，否则就是Happy Alex

#include<bits/stdc++.h>
using namespace std;
class P
{
    public:
    int n,m;
};
bool cmd(P x,P y)
{
    return x.n<y.n;
}
int main()
{
    P x[100005];
    int n;
    cin>>n;
    for(int i=1;i<=n;i++)
    {
        cin>>x[i].m>>x[i].n;
    }
    sort(x+1,x+1+n,cmd);
    for(int i=2;i<=n;i++)
    {
        if(x[i].m<x[i-1].m)
        {
            cout<<"Happy Alex"<<endl;
            return 0;
        }
    }
    cout<<"Poor Alex"<<endl;
    return 0;
}