LeetCode-Water and Jug Problem
Posted LiBlog
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了LeetCode-Water and Jug Problem相关的知识,希望对你有一定的参考价值。
You are given two jugs with capacities x and y litres. There is an infinite amount of water supply available. You need to determine whether it is possible to measure exactly z litres using these two jugs.
If z liters of water is measurable, you must have z liters of water contained within one or both buckets by the end.
Operations allowed:
- Fill any of the jugs completely with water.
- Empty any of the jugs.
- Pour water from one jug into another till the other jug is completely full or the first jug itself is empty.
Example 1: (From the famous "Die Hard" example)
Input: x = 3, y = 5, z = 4 Output: True
Example 2:
Input: x = 2, y = 6, z = 5 Output: False
Credits:
Special thanks to @vinod23 for adding this problem and creating all test cases.
Analysis:
It is a number theory problem.
https://discuss.leetcode.com/topic/49238/math-solution-java-solution/2
Solution:
public class Solution { public boolean canMeasureWater(int x, int y, int z) { if (x+y < z) return false; if (x==z || y==z || x+y==z) return true; return z%GCD(x,y)==0; } public int GCD(int x, int y){ while (x%y!=0){ int temp = x; x = y; y = temp%y; } return y; } }
以上是关于LeetCode-Water and Jug Problem的主要内容,如果未能解决你的问题,请参考以下文章
leetcode365. Water and Jug Problem
365. Water and Jug Problem (GCD or BFS) TBC
Leetcode: Water and Jug Problem && Summary: GCD求法(辗转相除法 or Euclidean algorithm)