遍历两个数组，并输出数组中的不同内容

Posted 2020-12-16 长城之上是千亿的星空，星空之上是不灭的守望。

 

[root@localhost ~]# cat a.log
a
ab
abc
ddd
[root@localhost ~]# 
[root@localhost ~]# cat b.log
a
ab
abc
ddd
dd
f
[root@localhost ~]# 
[root@localhost ~]# sh 1.sh
diff_list=dd f
[root@localhost ~]# cat 1.sh
my_tbs=(`cat a.log`) # my_tbs
all_tbs=(`cat b.log`) # all_tbs
 
declare -a diff_list
t=0
flag=0
for i in "${all_tbs[@]}"
do
 
    for j in "${my_tbs[@]}"
    do
         if [[ "${i}" == "${j}" ]]; then
            flag=1
            break
        fi
    done
    if [[ $flag -eq 0 ]]; then
        diff_list[t]=$i
        t=$((t+1))
    else
      flag=0
    fi
done

echo diff_list=${diff_list[@]}