1、查询表中重复数据。select * from people

where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)


2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录

delete from people

where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)

and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)


3、查找表中多余的重复记录(多个字段)

select * from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)


4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录

delete from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)



5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录

select * from vitae a

where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)


(二)

比方说

在A表中存在一个字段“name”,

而且不同记录之间的“name”值有可能会相同,

现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;

Select Name,Count(*) From A Group By Name Having Count(*) > 1


如果还查性别也相同大则如下:

Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1



(三)

方法一


declare @max integer,@id integer


declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1


open cur_rows


fetch cur_rows into @id,@max


while @@fetch_status=0


begin


select @max = @max -1


set rowcount @max


delete from 表名 where 主字段 = @id


fetch cur_rows into @id,@max


end


close cur_rows


set rowcount 0

方法二

"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。


1、对于第一种重复,比较容易解决,使用


select distinct * from tableName


就可以得到无重复记录的结果集。


如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除


select distinct * into #Tmp from tableName


drop table tableName


select * into tableName from #Tmp


drop table #Tmp


发生这种重复的原因是表
设计不周产生的,增加唯一索引列即可解决。


2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下


假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集


select identity(int,1,1) as autoID, * into #Tmp from tableName


select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID


select * from #Tmp where autoID in(select autoID from #tmp2)


最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)


(四)

查询重复


select * from tablename where id in (select id from tablename group by id


having count(id) > 1)