LeetCode-Expression Add Operators
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Given a string that contains only digits 0-9
and a target value, return all possibilities to add binary operators (not unary) +
, -
, or *
between the digits so they evaluate to the target value.
Examples:
"123", 6 -> ["1+2+3", "1*2*3"] "232", 8 -> ["2*3+2", "2+3*2"] "105", 5 -> ["1*0+5","10-5"] "00", 0 -> ["0+0", "0-0", "0*0"] "3456237490", 9191 -> []
Credits:
Special thanks to @davidtan1890 for adding this problem and creating all test cases.
Analysis:
Use recursion+backtracking. We need deal with
1. Numbers cannot start with 0
2. When do multiply, say previous value is x = a+b*c, in current layer, we get number d and do multiplying, the value should be x-b*c+b*c*d. So we need to carry the information of the last mulitplied number into next layer, i.e., b*c*d.
1 public class Solution { 2 public List<String> addOperators(String num, int target) { 3 List<String> resList = new ArrayList<String>(); 4 StringBuilder builder = new StringBuilder(); 5 addOperRecur(resList, num, target, builder, 0, 0, 0); 6 return resList; 7 } 8 9 public void addOperRecur(List<String> resList, String num, int target, StringBuilder builder, int pos, long value, 10 long lastMultipledNum) { 11 if (pos >= num.length() && value == target) { 12 resList.add(builder.toString()); 13 return; 14 } 15 16 int builderLen = builder.length(); 17 for (int i = pos; i < num.length(); i++) { 18 // only allow "0", not "0XXX". 19 if (i > pos && num.charAt(pos) == ‘0‘) 20 return; 21 long curNum = Long.parseLong(num.substring(pos, i + 1)); 22 if (pos == 0) { 23 builder.append(curNum); 24 addOperRecur(resList, num, target, builder, i + 1, curNum, curNum); 25 builder.setLength(builderLen); 26 } else { 27 builder.append(‘+‘).append(curNum); 28 addOperRecur(resList, num, target, builder, i + 1, value + curNum, curNum); 29 builder.setLength(builderLen); 30 31 builder.append(‘-‘).append(curNum); 32 addOperRecur(resList, num, target, builder, i + 1, value - curNum, -curNum); 33 builder.setLength(builderLen); 34 35 builder.append(‘*‘).append(curNum); 36 addOperRecur(resList, num, target, builder, i + 1, value - lastMultipledNum + lastMultipledNum * curNum, 37 lastMultipledNum * curNum); 38 builder.setLength(builderLen); 39 } 40 } 41 } 42 }
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