HDU 1228A + B

Posted 2020-06-13

题

Description

读入两个小于100的正整数A和B,计算A+B. 
需要注意的是:A和B的每一位数字由对应的英文单词给出. 

 

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 

 

Output

对每个测试用例输出1行,即A+B的值. 

 

Sample Input

one + two = three four + five six = zero seven + eight nine = zero + zero =

 

Sample Output

3 90 96

 

#include<stdio.h>
#include<string.h>
char str[1024],letter[10][10]= {"zero","one","two",
"three","four","five","six","seven","eight","nine"};
int flag,a,b,num;
int main()
{
    while(~scanf("%s",str))
    {
        if(strcmp(str,"="))//不为=
        {
            for(int i=0; i<10; i++)
                if(!strcmp(letter[i],str))//为数字i
                {
                    num=i;
                    if(!flag) a=a*10+num;//+前，统计i
                    else b=b*10+num;
                    break;
                }
            if(!strcmp(str,"+")) flag=!flag;//为+
        }
        else
        {
            if(!a&&!b)break;
            printf("%d\n",a+b);
            a=b=0;//不要忘记清零
        }
    }
    return 0;
}