191. 位1的个数

Posted 2020-11-27

 1 class Solution 
 2 {
 3 public:
 4     int hammingWeight(uint32_t n) 
 5     {
 6         int res = 0;
 7         for(int i = 0;i < 32;i ++) res += (n >> i) & 1;
 8         return res;
 9     }
10 };