Codeforces 707D - Persistent Bookcase

Posted 2020-08-04 DarkTong

在线版本：可持久化线段树。

 

/************************************************
Author        :DarkTong
Created Time  :2016/8/26 17:16:28
File Name     :D.cpp
*************************************************/

#include <bits/stdc++.h>
using namespace std;
typedef unsigned long long ULL;
typedef long long LL;
const int INF = 0x3f3f3f3f;
const double eps = 1e-9;
const int maxn = 100000 + 100;
int tr[maxn];
int sz = 0;
struct Node
{
    int l, r, s;
    bitset<1000 + 10> v;
//    Node(){l=r=s=0; memset(v, 0, sizeof(v));}
}nxt[maxn*20];

int getone(int x)
{
    int ans = 0;
    for(int i=0;i<32;++i)if(((x>>i)&1)==1) ++ans;
    return ans;
}
bitset<1000 + 10> Base;

void insert(int &x, int pre, int l, int r, int L, int R, int f, int j)
{
    x = ++sz;
    nxt[x] = nxt[pre];
//    cout<<"s:"<<nxt[x].s<<" l:"<<l<<" r:"<<r<<" L:"<<L<<" R:"<<R<<" ll:"<<nxt[x].l<<" rr:"<<nxt[x].r<<" pre:"<<pre<<endl;
//    cout<<"pl:"<<nxt[pre].l<<" pr:"<<nxt[pre].r<<endl;


    if(L<=l&&r<=R)
    {
        if(f==1)
        {
            if(!nxt[x].v.test(j)) nxt[x].s++, nxt[x].v.flip(j);
        }
        else if(f==2)
        {
            if(nxt[x].v.test(j)) nxt[x].s--, nxt[x].v.flip(j);
        }
        else if(f==3)
        {
            int ta = 0;
            for(int i=0;i<=j;++i) if(nxt[x].v.test(i)) ta++;
            nxt[x].s -= ta;
            nxt[x].s += j-ta+1;
            for(int i=0;i<=j;++i) nxt[x].v.flip(i);
        }
        return;
    }


    int m = (l+r)>>1;
    int tx = x;
//    cout<<"l:"<<l<<" m:"<<m<<" r:"<<r<<endl;
    if(L<m) insert(nxt[tx].l, nxt[pre].l, l, m, L, R, f, j);
    if(m<R) insert(nxt[tx].r, nxt[pre].r, m, r, L, R, f, j);
    nxt[tx].s = nxt[nxt[tx].l].s + nxt[nxt[tx].r].s;
}

int main()
{
    int T, cas=1;
    int n, m, q;
    scanf("%d%d%d", &n, &m, &q);
    for(int i=0;i<1000 + 10;++i) Base[i]=1;
    int op, i, j;
    for(int z=1;z<=q;++z)
    {
        scanf("%d%d", &op, &i);
        if(op<=2) scanf("%d", &j);
        else j=m;
        if(op<=3) insert(tr[z], tr[z-1], 1, n+1, i, i+1, op, j-1);
        else tr[z] = tr[i];

        printf("%d\n", nxt[tr[z]].s);
    }
    
    return 0;
}