Struts2使用OGNL遍历各种map总结
Posted
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Struts2使用OGNL遍历各种map总结相关的知识,希望对你有一定的参考价值。
一.Action中的代码:MapAction.java
package com.zx.demo.action;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import com.opensymphony.xwork2.ActionSupport;
import com.zx.demo.model.Product;
import com.zx.demo.model.Student;
public class MapAction extends ActionSupport
{
private
Map<String,String>
map;
private
Map<String,Student>
studentMap;
private
Map<String,String[]>
arrayMap;
private
Map<String,List<Student>>
listMap;
//这里省略get
set方法
public String testMap(){
map=new
HashMap<String,String>();
map.put("1", "one");
map.put("2", "two");
studentMap=new
HashMap<String,Student>();
studentMap.put("student1",new Student(new
Long(1),"20034140201","张三1","男",25));
studentMap.put("student2",new Student(new
Long(2),"20034140202","张三2","女",26));
studentMap.put("student3",new Student(new
Long(3),"20034140202","张三3","男",27));
arrayMap=new
HashMap<String,String[]>();
arrayMap.put("arr1", new
String[]{"1","2003401","leejie","male","20"});
arrayMap.put("arr2", new
String[]{"2","2003402","huanglie","male","25"});
arrayMap.put("arr3", new
String[{"3","2003403","lixiaoning","male","21"});
listMap=new
HashMap<String,List<Student>>();
List<Student> list1=new
ArrayList<Student>();
list1.add(new Student(new
Long(1),"20034140201","张三1","男",25));
list1.add(new Student(new
Long(2),"20034140202","张三2","男",25));
list1.add(new Student(new
Long(3),"20034140203","张三3","男",25));
listMap.put("class1",
list1);
List<Student> list2=new
ArrayList<Student>();
list2.add(new Student(new
Long(1),"20034140301","李四1","男",20));
list2.add(new Student(new
Long(2),"20034140302","李四2","男",21));
list2.add(new Student(new
Long(3),"20034140303","李四3","男",22));
list2.add(new Student(new
Long(4),"20034140304","李四4","男",23));
listMap.put("class2",
list2);
return SUCCESS;
}
}
二.前端测试页面:testMap.jsp
Java代码
<%@ page
contentType="text/html;charset=UTF-8"
%>
<%@ taglib prefix="s"
uri="/struts-tags" %>
<html>
<head>
<title>struts2中的map遍历总结</title>
</head>
<body>
<b>1.map中的key为String,value为String字符串</b><br>
<s:iterator value="map"
id="column">
<s:property
value="#column"/><br>
key:
<s:property
value="key"/><br>
value:<s:property
value="value"/><br>
</s:iterator>
******************************************<br>
<table border="1"
width="50%" cellspacing="0"
cellpadding="0">
<tr>
<td>key=value</td>
<td>ID</td>
<td>num</td>
<td>name</td>
<td>sex</td>
<td>age</td>
</tr>
******************************************<br>
<b>2.map中的key为String,value为Student对象</b>
<s:iterator value="studentMap"
id="column">
<tr>
<td>
<s:property
value="#column"/></td>
<td>
<s:property
value="value.id"/></td>
<td>
<s:property
value="value.num"/></td>
<td>
<s:property
value="value.name"/></td>
<td>
<s:property
value="value.sex"/></td>
<td>
<s:property
value="value.age"/></td>
</tr>
</s:iterator>
</table>
<p>
<table border="1" width="50%"
cellspacing="0" cellpadding="0">
<tr>
<td>key=value</td>
<td>ID</td>
<td>num</td>
<td>name</td>
<td>sex</td>
<td>age</td>
</tr>
******************************************<br>
<b>3.map中的key为String,value为String数组</b>
<s:iterator value="arrayMap"
id="column">
<tr>
<td><s:property
value="#column"/></td>
<td><s:property
value="value[0]"/></td>
<td><s:property
value="value[1]"/></td>
<td><s:property
value="value[2]"/></td>
<td><s:property
value="value[3]"/></td>
<td><s:property
value="value[4]"/></td>
</tr>
</s:iterator>
</table>
<p>
<table border="1" width="50%"
cellspacing="0" cellpadding="0">
<tr>
<td>class</td>
<td>ID</td>
<td>num</td>
<td>name</td>
<td>sex</td>
<td>age</td>
</tr>
******************************************<br>
<b>4.map中的key为String,value为list集合</b>
<s:iterator value="listMap"
id="column">
<s:set name="total"
value="#column.value.size"/>
<s:iterator value="#column.value"
status="s">
<tr>
<s:if
test="#s.first">
<td rowspan="${total}">
<s:property
value="#column.key"/>
</td>
</s:if>
<td>
<s:property value="id"/>
</td>
<td>
<s:property value="num"/>
</td>
<td>
<s:property value="name"/>
</td>
<td><s:property
value="sex"/></td>
<td><s:property
value="age"/></td>
</tr>
</s:iterator>
</s:iterator>
</table>
</body>
</html>
附:map的类型为Map<Integer,List(Menu)>在前端遍历,session.powerList存放的类型是:List(Menu)
<s:iterator value="map"
id="mapList">
<s:if
test="#mapList.key==0"><!-key为0的是父级菜单->
<s:iterator value="#mapList.value"
id="map">
<li
class="current"><!--遍历父级菜单,取得其名字-->
<b><s:property
value="#map.menuName"
/></b></a>
<ul>
<s:iterator value="#session.powerList"
id="power">
<!--遍历父级菜单下的所用子菜单-->
<s:if
test="#power.menuFatherId==#map.menuId">
<li><a
onClick="funFrame(‘admin/<s:property
value="#power.menuUrl" />‘)"
><s:property value="#power.menuName"
/></a>
</li>
</s:if>
</s:iterator>
</ul>
</li>
</s:iterator>
</s:if>
</s:iterator>
以上是关于Struts2使用OGNL遍历各种map总结的主要内容,如果未能解决你的问题,请参考以下文章