python 合并k个有序链表
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from heapq import heappush, heappop class Solution: def mergeKLists(self, lists): q = [] for i,head in enumerate(lists): if head: heappush(q, (head.val, i, head)) node = dummy = ListNode(0) while q: val, i, pop_node = heappop(q) print(val) node.next = ListNode(val) node = node.next next_node = pop_node.next if next_node: heappush(q, (next_node.val, i, next_node)) return dummy.next
为啥有i???????????理由见后、
另外PQ也有这个问题
# Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None import queue class Solution: def mergeKLists(self, lists: List[ListNode]) -> ListNode: q = queue.PriorityQueue() for i,head in enumerate(lists): if head: q.put((head.val, i, head)) node = dummy = ListNode(0) while not q.empty(): val, i, pop_node = q.get() node.next = ListNode(val) node = node.next next_node = pop_node.next if next_node: q.put((next_node.val, i, next_node)) return dummy.next
python 3 heappush Line 13: TypeError: ‘<‘ not supported between instances of ‘ListNode‘ and ‘ListNode‘
出现原因:
Last Edit: October 11, 2018 9:42 PM
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Python3 env will get TypeError: ‘<‘ not supported between instances of ‘ListNode‘ and ‘ListNode‘
if there are duplicate values in the list. Works in Python env.
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小C秋招面试算法题:合并k个有序数组合并k个有序链表(分治思想)
@cbmbbz In the event that two or more of the lists have the same
val
, this code will error out since thequeue
module will compare the second element in the priority queue which is aListNode
object (and this is not a comparable type).To solve for this issue, I have stored
(node.val, list_idx, node)
to account for this edge case.from queue import PriorityQueue # Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def mergeKLists(self, lists): k = len(lists) q = PriorityQueue(maxsize=k) dummy = ListNode(None) curr = dummy for list_idx, node in enumerate(lists): if node: q.put((node.val, list_idx, node)) while q.qsize() > 0: poped = q.get() curr.next, list_idx = poped[2], poped[1] curr = curr.next if curr.next: q.put((curr.next.val, list_idx, curr.next)) return dummy.next