python元祖

Posted 2022-12-28 raitorei

 

# 列表:有序,元素可以被修改
# 列表
# list
# li = [111,22,33,44]

# 元组:元素不可被修改,不能被增加或者删除
# ps:
# tuple
# tu = (11,22,33,44,22,22)
# print(tu.count(22)) #获取指定元素在元组中出现的次数
# print(tu.index(22))

###########  深灰魔法  ###########
# 1. 书写格式
# 一般写元组的时候，推荐在最后加入 ,
# 元素不可被修改，不能被增加或者删除
# tu = (111,"raito",(11,22),[(33,44)],True,33,44,)
# 2. 索引
# v = tu[0]
# print(v)

# 3. 切片
# v = tu[0:2]
# print(v)

# 4. 可以被for循环，可迭代对象
# for item in tu:
#     print(item)

# 5. 转换
# s = "asdfasdf0"
# li = ["asdf","asdfasdf"]
# tu = ("asdf","asdf")
#
# v = tuple(s)
# print(v)

# v = tuple(li)
# print(v)

# v = list(tu)
# print(v)

# v = "_".join(tu)
# print(v)

# li = ["asdf","asdfasdf"]
# li.extend((11,22,33,))
# print(li)

# 6.元组的一级元素不可修改/删除/增加
# tu = (111,"raitorei",(3,4),[(1,2)],True,7,11,)
# 元组，有序。
# v = tu[3][0][0]
# print(v)
# v=tu[3]
# print(v)
# tu[3][0] = 567
# print(tu)