Educational Codeforces Round 73 (Rated for Div. 2) A. 2048 Game
Posted ydddd
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Educational Codeforces Round 73 (Rated for Div. 2) A. 2048 Game相关的知识,希望对你有一定的参考价值。
链接:
https://codeforces.com/contest/1221/problem/A
题意:
You are playing a variation of game 2048. Initially you have a multiset s of n integers. Every integer in this multiset is a power of two.
You may perform any number (possibly, zero) operations with this multiset.
During each operation you choose two equal integers from s, remove them from s and insert the number equal to their sum into s.
For example, if s=1,2,1,1,4,2,2 and you choose integers 2 and 2, then the multiset becomes 1,1,1,4,4,2.
You win if the number 2048 belongs to your multiset. For example, if s=1024,512,512,4 you can win as follows: choose 512 and 512, your multiset turns into 1024,1024,4. Then choose 1024 and 1024, your multiset turns into 2048,4 and you win.
You have to determine if you can win this game.
You have to answer q independent queries.
思路:
将不大于2048的加起来判断
代码:
#include <bits/stdc++.h>
using namespace std;
int main()
int t, a, b, c;
cin >> t;
while (t--)
cin >> a >> b >> c;
if (a < b)
swap(a, b);
c += (a-b);
a = b;
int sum = min(a, c);
a -= sum, b -= sum, c -= sum;
cout << sum+(a+b)/3 << endl;
return 0;
以上是关于Educational Codeforces Round 73 (Rated for Div. 2) A. 2048 Game的主要内容,如果未能解决你的问题,请参考以下文章
Educational Codeforces Round 7 A
Educational Codeforces Round 7
Educational Codeforces Round 90
Educational Codeforces Round 33