模拟爱与愁的一千个伤心的理由
Posted gongdakai
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了模拟爱与愁的一千个伤心的理由相关的知识,希望对你有一定的参考价值。
思路
这道题的题目我是真的无力吐槽,但是,这道题真心不错QAQ。
这道题不难,但很考验耐心与细心,有各种各样的小错误,如果不细心都不会发现,我最开始的代码只得了60分,就是忽略了好几个情况,然后反复测试数据,才AC的QAQ(也许只是因为我太弱了)
值得一刷
Code
#include<iostream>
#include<cstdio>
#include<string>
#include<vector>
#include<algorithm>
#include<cstdlib>
#include<cmath>
#include<stack>
#include<map>
using namespace std;
int n;
int s[5];
string a[25]="","one","two","three",
"four","five","six","seven","eight","nine",
"ten","eleven","twelve","thirteen","fourteen",
"fifteen","sixteen","seventeen","eighteen","nineteen";
string x[20]="","","twenty","thirty","forty","fifty",
"sixty","seventy","eighty","ninety";
int main()
cin>>n;
int i=4;
while(n!=0)
s[i]=n%10;
n/=10;
i--;
if(s[1]!=0)
cout<<a[s[1]]<<" thousand ";
if(s[2]!=0)
cout<<a[s[2]]<<" hundred ";
else if(s[3]!=0&&s[4]!=0&&(s[2]!=0||s[1]!=0))
cout<<"and ";
if(s[3]==0&&s[4]!=0&&(s[2]!=0||s[1]!=0))
cout<<"and "<<a[s[4]]<<endl;
else if(s[3]==0&&s[4]!=0)
cout<<a[s[4]]<<endl;
else if(s[3]==1)
cout<<a[s[4]+10]<<endl;
else if(s[4]!=0)
cout<<x[s[3]]<<" "<<a[s[4]];
if(s[1]==0&&s[2]==0&&s[3]==0&&s[4]==0)
cout<<"zero";
return 0;
以上是关于模拟爱与愁的一千个伤心的理由的主要内容,如果未能解决你的问题,请参考以下文章