fastjson将json格式字符串转成list集合

Posted 2022-12-21 qingmuchuanqi48

 1.gameListStr = "["gameId":"1","gameName":"哈哈","gameId":"2","gameName":"呵呵"]";
2. List<Game> gameList = JSONObject.parseArray(gameListStr, Game.class);

public class Game 
   public String gameId;
   public String gameName;

   public String getGameId() 
      return gameId;
   

   public void setGameId(String gameId) 
      this.gameId = gameId;
   

   public String getGameName() 
      return gameName;
   

   public void setGameName(String gameName) 
      this.gameName = gameName;