LuoguP3690 模板Link Cut Tree (LCT)
Posted bingoyes
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了LuoguP3690 模板Link Cut Tree (LCT)相关的知识,希望对你有一定的参考价值。
勉强算是结了个大坑吧
或者才开始
#include <cstdio>
#include <iostream>
#include <cstring>
#include <algorithm>
#include <cmath>
#define R(a,b,c) for(register int a = (b); (a) <= (c); ++(a))
#define nR(a,b,c) for(register int a = (b); (a) >= (c); --(a))
#define Fill(a,b) memset(a, b, sizeof(a))
#define Swap(a,b) ((a) ^= (b) ^= (a) ^= (b))
#define ll long long
#define u32 unsigned int
#define u64 unsigned long long
#define ON_DEBUGG
#ifdef ON_DEBUGG
#define D_e_Line printf("\n----------\n")
#define D_e(x) cout << (#x) << " : " << x << endl
#define Pause() system("pause")
#define FileOpen() freopen("in.txt", "r", stdin)
#define FileSave() freopen("out.txt", "w", stdout)
#include <ctime>
#define TIME() fprintf(stderr, "\ntime: %.3fms\n", clock() * 1000.0 / CLOCKS_PER_SEC)
#else
#define D_e_Line ;
#define D_e(x) ;
#define Pause() ;
#define FileOpen() ;
#define FileSave() ;
#define TIME() ;
//char buf[1 << 21], *p1 = buf, *p2 = buf;
//#define getchar() (p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 1 << 21, stdin), p1 == p2) ? EOF : *p1++)
#endif
using namespace std;
struct ios
template<typename ATP>inline ios& operator >> (ATP &x)
x = 0; int f = 1; char ch;
for(ch = getchar(); ch < '0' || ch > '9'; ch = getchar()) if(ch == '-') f = -1;
while(ch >= '0' && ch <= '9') x = x * 10 + (ch ^ '0'), ch = getchar();
x *= f;
return *this;
io;
template<typename ATP>inline ATP Max(ATP a, ATP b)
return a > b ? a : b;
template<typename ATP>inline ATP Min(ATP a, ATP b)
return a < b ? a : b;
template<typename ATP>inline ATP Abs(ATP a)
return a < 0 ? -a : a;
const int N = 300007;
struct node
int ch[2], fa, val, sum;
bool rev;
t[N];
#define ls t[u].ch[0]
#define rs t[u].ch[1]
inline bool Ident(int u)
return t[t[u].fa].ch[1] == u;
inline bool IsRoot(int u)
return t[t[u].fa].ch[0] != u && t[t[u].fa].ch[1] != u;
inline void Pushup(int u)
t[u].sum = t[u].val ^ t[ls].sum ^ t[rs].sum;
inline void Pushrev(int u)
Swap(t[u].ch[0], t[u].ch[1]);
t[u].rev ^= 1;
inline void Pushdown(int u)
if(!t[u].rev) return;
if(t[u].ch[0]) Pushrev(t[u].ch[0]);
if(t[u].ch[1]) Pushrev(t[u].ch[1]);
t[u].rev = 0;
int sta[N], top;
inline void Rotate(int x)
int y = t[x].fa, z = t[y].fa, k = Ident(x);
t[x].fa = z; if(!IsRoot(y)) t[z].ch[Ident(y)] = x;
t[y].ch[k] = t[x].ch[k ^ 1], t[t[x].ch[k ^ 1]].fa = y;
t[x].ch[k ^ 1] = y, t[y].fa = x;
Pushup(y), Pushup(x);
inline void Splay(int u)
int x = u;
top = 0;
while(!IsRoot(u))
sta[++top] = u;
u = t[u].fa;
sta[++top] = u;
nR(i,top,1)
Pushdown(sta[i]);
while(!IsRoot(x))
int y = t[x].fa;
if(!IsRoot(y))
Ident(x) == Ident(y) ? Rotate(y) : Rotate(x);
Rotate(x);
Pushup(x);
inline void Access(int u)
for(int v = 0; u; v = u, u = t[u].fa)
Splay(u);
t[u].ch[1] = v;
Pushup(u);
inline void MakeRoot(int u)
Access(u);
Splay(u);
Pushrev(u);
inline int FindRoot(int u)
Access(u);
Splay(u);
while(ls) u = ls;
Splay(u);
return u;
inline void Split(int u, int v)
MakeRoot(u);
Access(v);
Splay(v);
inline void Link(int u, int v)
Split(u, v);
t[u].fa = v;
inline void Cut(int u, int v)
MakeRoot(u);
if(FindRoot(v) == u && t[v].fa == u && !t[v].ch[0])
t[v].fa = t[u].ch[1] = 0;
Pushup(u);
inline void Modify(int u, int w)
// Access(u);
Splay(u);
t[u].val = w;
Pushup(u);
int main()
//FileOpen();
//FileSave();
int n, m;
io >> n >> m;
R(i,1,n)
io >> t[i].val;
t[i].sum = t[i].val;
while(m--)
int opt, x, y;
io >> opt >> x >> y;
switch(opt)
case 0:
Split(x, y);
printf("%d\n", t[y].sum);
break;
case 1:
Link(x, y);
break;
case 2:
Cut(x, y);
break;
case 3:
Modify(x, y);
break;
return 0;
以上是关于LuoguP3690 模板Link Cut Tree (LCT)的主要内容,如果未能解决你的问题,请参考以下文章
luoguP3690 模板Link Cut Tree (动态树)[LCT]
luogu3690 模板Link Cut Tree (动态树)