908. Smallest Range I - LeetCode
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Description:
Given an array A
of integers, for each integer A[i]
we may choose any x
with -K <= x <= K
, and add x
to A[i]
.
After this process, we have some array B
.
Return the smallest possible difference between the maximum value of B
and the minimum value of B
.
Example 1:
Input: A = [1], K = 0
Output: 0
Explanation: B = [1]
Example 2:
Input: A = [0,10], K = 2
Output: 6
Explanation: B = [2,8]
Example 3:
Input: A = [1,3,6], K = 3
Output: 0
Explanation: B = [3,3,3] or B = [4,4,4]
Note:
1 <= A.length <= 10000
0 <= A[i] <= 10000
0 <= K <= 10000
Accepted
29,142
Submissions
44,849
Solution:
class Solution public int smallestRangeI(int[] A, int K) if(A==null||A.length==1) return 0; Arrays.sort(A); int second = A[0]; int first = A[A.length -1]; if((first - second)<=2*K) return 0 ; else return first - second - K - K ;
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