PAT 甲级 1058 A+B in Hogwarts (20 分) (简单题)
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If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it‘s easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut
(Galleon
is an integer in [0], Sickle
is an integer in [0, 17), and Knut
is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
题意:
17个Sickle对换一个Galleon,29个Knut对换一个Sickle。根据Galleon.Sickle.Knut的方式相加A和B
分析:把A和B都化为Knut的形式,然后相加,最后转换为Galleon.Sickle.Knut的形式。
AC代码:
#include<iostream> using namespace std; int a1,b1,c1,a2,b2,c2; int main() scanf("%d.%d.%d %d.%d.%d",&a1,&b1,&c1,&a2,&b2,&c2); a1+=a2; b1+=b2; c1+=c2; int x=c1/29; c1-=x*29; b1+=x; x=b1/17; b1-=x*17; a1+=x; printf("%d.%d.%d",a1,b1,c1); return 0;
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