leetcode 20. Valid Parentheses

Posted 2022-11-13 qinduanyinghua

Given a string containing just the characters ‘(‘, ‘)‘, ‘‘, ‘‘, ‘[‘ and ‘]‘, determine if the input string is valid.

An input string is valid if:

1. Open brackets must be closed by the same type of brackets.
2. Open brackets must be closed in the correct order.

Note that an empty string is also considered valid.

Example 1:

Input: "()"
Output: true

Example 2:

Input: "()[]"
Output: true

Example 3:

Input: "(]"
Output: false

Example 4:

Input: "([)]"
Output: false

Example 5:

Input: "[]"
Output: true

思路：栈实现

 1 class Solution 
 2 public:
 3     bool isValid(string s) 
 4         stack<char> st;
 5         int len = s.length();
 6         for (int i = 0; i < len; ++i) 
 7             if (!st.empty()) 
 8                 if (s[i] == ‘(‘ || s[i] == ‘‘ || s[i] == ‘[‘) 
 9                     st.push(s[i]);
10                  else if ((s[i] == ‘)‘ && st.top() == ‘(‘) ||
11                            (s[i] == ‘‘ && st.top() == ‘‘) ||
12                            (s[i] == ‘]‘ && st.top() == ‘[‘)) 
13                     st.pop();
14                  else 
15                     st.push(s[i]);
16                 
17              else 
18                 st.push(s[i]);
19             
20         
21         if (st.empty())
22             return true;
23         else
24             return false;
25     
26 ;