leetcode 7. Reverse Integer
Posted qinduanyinghua
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了leetcode 7. Reverse Integer相关的知识,希望对你有一定的参考价值。
Given a 32-bit signed integer, reverse digits of an integer.
Example 1:
Input: 123 Output: 321
Example 2:
Input: -123 Output: -321
Example 3:
Input: 120 Output: 21
Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
1 class Solution 2 public: 3 int reverse(int x) 4 int rev = 0; 5 while (x != 0) 6 int pop = x % 10; 7 x /= 10; 8 if (rev > INT_MAX / 10 || (rev == INT_MAX / 10 && pop > INT_MAX % 10)) 9 return 0; 10 if (rev < INT_MIN / 10 || (rev == INT_MIN / 10 && pop < INT_MIN % 10)) 11 return 0; 12 rev = rev * 10 + pop; 13 14 return rev; 15 16 ;
以上是关于leetcode 7. Reverse Integer的主要内容,如果未能解决你的问题,请参考以下文章