使用$.ajax方式实现页面异步访问，局部更新的效果
Posted newcityboy
tags:
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<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
<script src="js/jquery-3.3.1.min.js"></script>
<script>
function fun()
$.ajax(
url:"ajaxServlet",
type:"POST",
data:
"username":"light",
"age":12
,
success:function (data)
alert(data);
,
error:function ()
alert("出错啦");
,
dataType:"text"
);
);
</script>
</head>
<body>
<input type="button" value="发送异步请求" onclick="fun();">
<input type="text">
</body>
</html>
package cn.hopetesting.com;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
/**
* @author newcityman
* @date 2019/9/16 - 21:53
*/
@WebServlet("/ajaxServlet")
public class AjaxServlet extends HttpServlet
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
String username = request.getParameter("username");
try
Thread.sleep(5000);
catch (InterruptedException e)
e.printStackTrace();
System.out.println(username);
response.getWriter().write("hello,"+username+".");
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
this.doPost(request, response);
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