JS获取URL链接参数

Posted 2022-11-04 yxknotes

 

* **使用范例**：
*
*      @example
*      var getParameter=new getparameter();
*      var fromId=getParameter.from;
*/

function Getparameter(key)
    var QueryString = 
        data: ,
        Initial: function() 
            var aPairs,aTmp,a;
            var queryString = location.search;
            queryString = queryString.substr(1, queryString.length);
            aPairs = queryString.split("&");
            for (var i = 0; i < aPairs.length; i++) 
                aTmp = aPairs[i].split("=");
                this.data[aTmp[0]] = aTmp[1];
            
        ,
        GetValue: function(key) 
            return QueryString.data[key];
        
    ;
    QueryString.Initial();
    return QueryString.data