寻找重复的子树(dfs)

Posted 2022-10-26 letlifestop

题目连接：

https://leetcode-cn.com/problems/find-duplicate-subtrees/

题目大意：

中文题

具体思路：

将每一颗子树转换成字符串，然后通过unordered_map去重即可（map的速度较慢）

AC代码：

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode 
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) 
 8  * ;
 9  */
10 class Solution 
11 public:
12     vector<TreeNode*> findDuplicateSubtrees(TreeNode* root) 
13         
14         vector<TreeNode*>ans;
15         unordered_map<string,int>vis;
16         
17         dfs(root, ans, vis);
18         
19         return ans;
20     
21     string dfs(TreeNode* root, vector<TreeNode*>&ans, unordered_map<string,int>&vis)
22         
23         if(root == NULL)
24             return "#";
25         
26         string tmp = to_string(root->val) + dfs(root->left, ans, vis) + dfs(root->right, ans, vis);
27         
28         if(vis[tmp] == 1) 
29             ans.push_back(root);
30         vis[tmp]++;
31         
32         return tmp;
33     
34 ;