python文件夹操作

Posted 2022-10-16 weihuang6620

1.遍历文件夹下所有文件
2.将后缀为.DCM的文件复制到指定文件夹

import os
import shutil

def all_path(dirname):
    result = []#所有的文件
    for maindir, subdir, file_name_list in os.walk(dirname):

        # print("1:",maindir) #当前主目录
        # print("2:",subdir) #当前主目录下的所有目录
        # print("3:",file_name_list)  #当前主目录下的所有文件

        if len(subdir) == 0 and len(file_name_list) < 5:
            for filename in file_name_list:
                apath = os.path.join(maindir, filename)#合并成一个完整路径
                result.append(apath)
        elif len(subdir) > 0:
            for filename in file_name_list:
                apath = os.path.join(maindir, filename)  # 合并成一个完整路径
                result.append(apath)
        else:
            continue

    return result


def copy(all_list):
    new_path = r‘/media/awifi/40FD960833674C19/workspace/示范区柯桥确诊/DR_FOR_TEST‘

    for i in all_list:
        if not i.endswith(‘.DCM‘):
            continue
        else:
            print(i)
            name = os.path.basename(i)
            new_name = new_path + ‘/‘ + name
            shutil.copyfile(i, new_name)

if __name__ == ‘__main__‘:
    result = all_path("/media/awifi/40FD960833674C19/workspace/示范区柯桥确诊/DR")
    copy(result)