自定义 RestTemplate 异常处理 （转）

Posted 2022-10-09 guanbin-529

转自：https://ethendev.github.io/2018/11/06/RestTemplate-error-handler/

一些 API 的报错信息通过 Response 的 body返回。使用 HttpClient 能正常获取到 StatusCode 和 body 中的错误提示。然而使用 RestTemplate ，会直接抛出下面的异常。如果想获取原始的信息并进一步处理会比较麻烦。

org.springframework.web.client.HttpClientErrorException: 404 null
    at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:94)
    at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:79)
    at org.springframework.web.client.ResponseErrorHandler.handleError(ResponseErrorHandler.java:63)
    at org.springframework.web.client.RestTemplate.handleResponse(RestTemplate.java:777)
    at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:730)
    at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:704)
    at org.springframework.web.client.RestTemplate.exchange(RestTemplate.java:621)

RestTemplate 异常处理流程

下面看一下原因， RestTemplate 中的 getForObject, getForEntity 和 exchange 等常用方法最终都是调用 doExecute 方法。下面是 doExecute 方法源码

public class RestTemplate extends InterceptingHttpAccessor implements RestOperations 

    private ResponseErrorHandler errorHandler;
    ......
    
    @Nullable
    protected <T> T doExecute(URI url, @Nullable HttpMethod method, @Nullable RequestCallback requestCallback, @Nullable ResponseExtractor<T> responseExtractor) throws RestClientException 
        Assert.notNull(url, "‘url‘ must not be null");
        Assert.notNull(method, "‘method‘ must not be null");
        ClientHttpResponse response = null;

        String resource;
        try 
            ClientHttpRequest request = this.createRequest(url, method);
            if (requestCallback != null) 
                requestCallback.doWithRequest(request);
            

            response = request.execute();
            // 处理 Response
            this.handleResponse(url, method, response);
            if (responseExtractor != null) 
                Object var14 = responseExtractor.extractData(response);
                return var14;
            

            resource = null;
         catch (IOException var12) 
            resource = url.toString();
            String query = url.getRawQuery();
            resource = query != null ? resource.substring(0, resource.indexOf(63)) : resource;
            throw new ResourceAccessException("I/O error on " + method.name() + " request for \"" + resource + "\": " + var12.getMessage(), var12);
         finally 
            if (response != null) 
                response.close();
            

        

        return resource;
    

    protected void handleResponse(URI url, HttpMethod method, ClientHttpResponse response) throws IOException 
        ResponseErrorHandler errorHandler = this.getErrorHandler();
        boolean hasError = errorHandler.hasError(response);
        if (this.logger.isDebugEnabled()) 
            try 
                this.logger.debug(method.name() + " request for \"" + url + "\" resulted in " + response.getRawStatusCode() + " (" + response.getStatusText() + ")" + (hasError ? "; invoking error handler" : ""));
             catch (IOException var7) 
                ;
            
        
        // 异常处理
        if (hasError) 
            errorHandler.handleError(url, method, response);
        

    

从下面的代码可以看出，DefaultResponseErrorHandler 捕获并抛出了异常。

public class DefaultResponseErrorHandler implements ResponseErrorHandler 
    ...
    
    protected void handleError(ClientHttpResponse response, HttpStatus statusCode) throws IOException 
        switch(statusCode.series()) 
        case CLIENT_ERROR:
            throw new HttpClientErrorException(statusCode, response.getStatusText(), response.getHeaders(), this.getResponseBody(response), this.getCharset(response));
        case SERVER_ERROR:
            throw new HttpServerErrorException(statusCode, response.getStatusText(), response.getHeaders(), this.getResponseBody(response), this.getCharset(response));
        default:
            throw new UnknownHttpStatusCodeException(statusCode.value(), response.getStatusText(), response.getHeaders(), this.getResponseBody(response), this.getCharset(response));
        
    

如果想自己捕获异常信息，自己处理异常的话可以通过实现 ResponseErrorHandler 类来实现。其源码如下：

 

public interface ResponseErrorHandler 

    // 标示 Response 是否存在任何错误。实现类通常会检查 Response 的 HttpStatus。
    boolean hasError(ClientHttpResponse var1) throws IOException;

    // 处理 Response 中的错误, 当 HasError 返回 true 时才调用此方法。
    void handleError(ClientHttpResponse var1) throws IOException;

    // handleError 的替代方案，提供访问请求URL和HTTP方法的额外信息。
    default void handleError(URI url, HttpMethod method, ClientHttpResponse response) throws IOException 
        this.handleError(response);
    

自定义 RestTemplate 异常处理

如果想像 HttpClient 一样直接从 Response 获取 HttpStatus 和 body 中的报错信息 而不抛出异常，可以通过下面的代码实现：

public class CustomErrorHandler implements ResponseErrorHandler 

    @Override
    public boolean hasError(ClientHttpResponse response) throws IOException 
        return true;
    

    @Override
    public void handleError(ClientHttpResponse response) throws IOException 

    

设置 RestTemplate 的异常处理类

restTemplate.setErrorHandler(new CustomErrorHandler());
ResponseEntity<String> response = restTemplate.exchange(uri, HttpMethod.GET, null, String.class);
System.out.println(response.getBody());

输出结果

"code":404,"result":null,"message":"Resources not found"