(Easy) Guess Number Higher or Lower -LeetCode
Posted codingyangmao
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了(Easy) Guess Number Higher or Lower -LeetCode相关的知识,希望对你有一定的参考价值。
Description:
We are playing the Guess Game. The game is as follows:
I pick a number from 1 to n. You have to guess which number I picked.
Every time you guess wrong, I‘ll tell you whether the number is higher or lower.
You call a pre-defined API guess(int num)
which returns 3 possible results (-1
, 1
, or 0
):
-1 : My number is lower 1 : My number is higher 0 : Congrats! You got it!
Example :
Input: n = 10, pick = 6
Output: 6
Solution:
Key algorithm used: Binary Search:
/* The guess API is defined in the parent class GuessGame. @param num, your guess @return -1 if my number is lower, 1 if my number is higher, otherwise return 0 int guess(int num); */ public class Solution extends GuessGame public int guessNumber(int n) int start = 1; int end = n; while ( start< end ) int mid = start +(end - start)/2; if(guess(mid)== 1) start = mid+1; else if(guess(mid)==-1) end = mid; else if(guess(mid)==0) return mid; return start;
以上是关于(Easy) Guess Number Higher or Lower -LeetCode的主要内容,如果未能解决你的问题,请参考以下文章