利用倒除法将一个十进制数的正整数转换为二进制

Posted 2022-09-12 tanghaiyong

#include <iostream>
#include <Windows.h>

using namespace std;

int main(void) 
    int n = 0;
    int ret[32];
    int i = 0;

    cout << "请输入一个正整数：";
    cin >> n;

    while (n != 0)
    
        ret[i] = n % 2;
        n = n / 2;
        i++;
    

    for (i--; i >= 0; i--) 
        cout << ret[i];
    
    cout << endl;

    system("pause");
    return 0;