Java 获取网络重定向URL(302重定向)

Posted 2022-09-08 fnlingnzb-learner

方法1：

 1 import java.net.HttpURLConnection;
 2 import java.net.URL;
 3  
 4 import org.junit.Assert;
 5 import org.junit.Test;
 6  
 7 public class GetRedirectUrlTest 
 8     @Test
 9     public void test_getRedirectUrl() throws Exception 
10         String url="http://www.baidu.com/link?url=ByBJLpHsj5nXx6DESXbmMjIrU5W4Eh0yg5wCQpe3kCQMlJK_RJBmdEYGm0DDTCoTDGaz7rH80gxjvtvoqJuYxK";
11         String expectUrl="http://www.zhihu.com/question/20583607/answer/16597802";
12         String redictURL = getRedirectUrl(url);
13         Assert.assertEquals(expectUrl, redictURL);
14     
15     
16     /**
17      * 获取重定向地址
18      * @param path
19      * @return
20      * @throws Exception
21      */
22     private String getRedirectUrl(String path) throws Exception 
23         HttpURLConnection conn = (HttpURLConnection) new URL(path)
24                 .openConnection();
25         conn.setInstanceFollowRedirects(false);
26         conn.setConnectTimeout(5000);
27         return conn.getHeaderField("Location");
28     
29 

 

方法2：

 1 /**
 2      * 处理跳转链接，获取重定向地址
 3      * @param url   源地址
 4      * @return      目标网页的绝对地址
 5      */
 6     public String getAbsUrl(String url)
 7         CloseableHttpClient httpclient = HttpClients.createDefault();
 8         HttpClientContext context = HttpClientContext.create();
 9         HttpGet httpget = new HttpGet(url);
10         CloseableHttpResponse response = null;
11         String absUrl = null;
12         try 
13             response = httpclient.execute(httpget, context);
14             HttpHost target = context.getTargetHost();
15             List<URI> redirectLocations = context.getRedirectLocations();
16             URI location = URIUtils.resolve(httpget.getURI(), target, redirectLocations);
17             System.out.println("Final HTTP location: " + location.toASCIIString());
18             absUrl = location.toASCIIString();          
19         catch(IOException e)
20             e.printStackTrace();
21         catch (URISyntaxException e)          
22             e.printStackTrace();
23         finally 
24             try 
25                 httpclient.close();
26                 response.close();
27              catch (IOException e)                
28                 e.printStackTrace();
29             
30         
31         return absUrl;
32