Java中时间格式处理，指定N天/小时等之后的时间

Posted 2022-09-04 qianjinyan

1）根据当前时间，获取具体的时刻的时间

N天前

M小时之前

可用

new Date().getTime() - 24 * 60 * 60 * 1000*N【N天之前】
的方法来获取处理时间之后的具体的值，
最终转化为想要的时间格式

import java.text.SimpleDateFormat;
import java.util.Date;

public class getTime 

    public static void main(String[] args) 

        SimpleDateFormat sd = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        Date time = new Date(new Date().getTime() - 24 * 60 * 60 * 1000);
        System.out.println(sd.format(time));
        System.out.println(sd.format(new Date()));


        //想获得N天之前或M天之后的时间
        int NDay = 5;
        int MDay = -10; //之后就传负数

        Date timeN = new Date(new Date().getTime() - 24 * 60 * 60 * 1000 * NDay);
        Date timeM = new Date(new Date().getTime() - 24 * 60 * 60 * 1000 * MDay);

        System.out.println(sd.format(timeN));
        System.out.println(sd.format(timeM));


        //想获得N小时之前或M小时之后的时间
        int NHour = 5;
        int MHour = -10; //之后就传负数

        Date timeNHour = new Date(new Date().getTime() - 60 * 60 * 1000 * NHour);
        Date timeMHour = new Date(new Date().getTime() - 60 * 60 * 1000 * MHour);
        System.out.println(sd.format(timeNHour));
        System.out.println(sd.format(timeMHour));


        //想获得N分钟之前或M分钟之后的时间
        int NMinute = 5;
        int MMinute = -10; //之后就传负数

        Date timeNMinute = new Date(new Date().getTime() - 60 * 1000 * NMinute);
        Date timeMMiute = new Date(new Date().getTime() - 60 * 1000 * MMinute);
        System.out.println(sd.format(timeNMinute));
        System.out.println(sd.format(timeMMiute));


        //想获得N秒之前或M秒之后的时间
        int NSecond = 5;
        int MSecond = -10; //之后就传负数

        Date timeNSecond = new Date(new Date().getTime() - 1000 * NSecond);
        Date timeMSecond = new Date(new Date().getTime() - 1000 * MSecond);
        System.out.println(sd.format(timeNSecond));
        System.out.println(sd.format(timeMSecond));

        long Ntime = getDetailtime(3, 20, 1, 1);
        System.out.println(sd.format(Ntime));
        System.out.println(Ntime);

        Date Ntime2 = getDetailDate(3, 20, 1, 1);
        System.out.println(sd.format(Ntime2));
        System.out.println(Ntime2);

    


    public static Date getDetailDate(int Day, int Hour, int Minute, int Second) 
        Date timeN = new Date(new Date().getTime() - Day * 24 * 60 * 60 * 1000 - Hour * 60 * 60 * 1000 - Minute * 60 * 1000 - Second * 1000);
        return timeN;
    


    public static long getDetailtime(int Day, int Hour, int Minute, int Second) 
        long timeN = new Date().getTime() - Day * 24 * 60 * 60 * 1000 - Hour * 60 * 60 * 1000 - Minute * 60 * 1000 - Second * 1000;
        return timeN;
    

　　那么想要更加具体的时间，比如让用户输入具体的天，时，分钟，秒等，可以获取更加精准的想要的时刻

public static Date getDetailDate(int Day, int Hour, int Minute, int Second) 
        Date timeN = new Date(new Date().getTime() - Day * 24 * 60 * 60 * 1000 - Hour * 60 * 60 * 1000 - Minute * 60 * 1000 - Second * 1000);
        return timeN;
    


    public static long getDetailtime(int Day, int Hour, int Minute, int Second) 
        long timeN = new Date().getTime() - Day * 24 * 60 * 60 * 1000 - Hour * 60 * 60 * 1000 - Minute * 60 * 1000 - Second * 1000;
        return timeN;
    

　　

2） 根据

java.util.Calendar中的操作

ca.add(Calendar.DATE, -N);【减去N天】

import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;

public class getTime2 

    public static void main(String[] args) 

        SimpleDateFormat sd = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        int N=2;

        Calendar ca = Calendar.getInstance();//得到一个Calendar的实例
        ca.setTime(new Date()); //设置时间为当前时间
        ca.add(Calendar.DATE, -N);
        long timeDay= ca.getTime().getTime();

        Calendar ca2 = Calendar.getInstance();//得到一个Calendar的实例
        ca2.setTime(new Date()); //设置时间为当前时间
        ca2.add(Calendar.HOUR, -N);
        long timeDay2= ca2.getTime().getTime();


        Calendar ca3 = Calendar.getInstance();//得到一个Calendar的实例
        ca3.setTime(new Date()); //设置时间为当前时间
        ca3.add(Calendar.MINUTE, -N);
        long timeDay3= ca3.getTime().getTime();

        Calendar ca4 = Calendar.getInstance();//得到一个Calendar的实例
        ca4.setTime(new Date()); //设置时间为当前时间
        ca4.add(Calendar.SECOND, -N);
        long timeDay4= ca4.getTime().getTime();

        System.out.println(sd.format(timeDay));
        System.out.println(sd.format(timeDay2));
        System.out.println(sd.format(timeDay3));
        System.out.println(sd.format(timeDay4));


        Calendar ca5 = Calendar.getInstance();//得到一个Calendar的实例
        ca5.setTime(new Date()); //设置时间为当前时间
        ca5.add(Calendar.MONTH, -N);
        long timeDay5= ca5.getTime().getTime();
        System.out.println(sd.format(timeDay5));


        Calendar ca6 = Calendar.getInstance();//得到一个Calendar的实例
        ca6.setTime(new Date()); //设置时间为当前时间
        ca6.add(Calendar.YEAR, -N);
        long timeDay6= ca6.getTime().getTime();
        System.out.println(sd.format(timeDay6));

    

　　

 

3）Java中long类型的10位和13位的时间戳，转换为可供查看的时间格式

如果接口文档中规定的是String类型，要注意一定不能含有l，只能含有数字

public static String timestamp2Date(String str_num) 
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        if (str_num.length() == 13) 
            String date = sdf.format(new Date(toLong(str_num)));
            System.out.println("将13位时间戳:" + str_num + "转化为字符串:" + date);
            return date;
         else 
            String date = sdf.format(new Date(toLong(str_num) * 1000));
            System.out.println("将10位时间戳:" + str_num + "转化为字符串:" + date);
            return date;
        
    

    public static long toLong(String obj) 
         return Long.parseLong(obj);
    

    @Test
    public void Te()
        String aaa = "1566802997242";
        String bbb = "1566801239";
        System.out.println(aaa.length());
        System.out.println(bbb.length());
        timestamp2Date(aaa);
        timestamp2Date(bbb);