145. Binary Tree Postorder Traversal

Posted 2022-09-04 wentiliangkaihua

Given a binary tree, return the postorder traversal of its nodes‘ values.

Example:

Input: [1,null,2,3]
   1
         2
    /
   3

Output: [3,2,1]

class Solution 
    public List<Integer> postorderTraversal(TreeNode root) 
        if (root == null) return new LinkedList();
        Stack<TreeNode> s = new Stack<TreeNode>();
        LinkedList<Integer> res = new LinkedList();
        s.push(root);
        while(!s.empty())
            TreeNode p = s.pop();
            res.addFirst(p.val);
            //左右根，push进stack是第一次逆，addFirst又逆回来，所以还是左右根
            if(p.left != null)
                s.push(p.left);
            
            if(p.right != null)
                s.push(p.right);
            
        
        return res;
    

LinkedList有addFirst方法，巧妙。