linq lanbda表达式的用法

Posted 人本善良

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了linq lanbda表达式的用法相关的知识,希望对你有一定的参考价值。

 

 

1、 查询Student表中的所有记录的Sname、Ssex和Class列。
select 
sname,ssex,class from student
Linq:
    from s 
in Students
    select new {
        s.SNAME,
        
s.SSEX,
        s.CLASS
    }
Lambda:
    Students.Select( s => new {
        
SNAME = s.SNAME,SSEX = s.SSEX,CLASS = s.CLASS
    })



2、 
查询教师所有的单位即不重复的Depart列。
select 
distinct depart from teacher
Linq:
    from t 
in Teachers.Distinct()
    select t.DEPART
Lambda:
    Teachers.Distinct().Select( t => 
t.DEPART)


 


3、 
查询Student表的所有记录。
select * 
from student
Linq:
    from s in Students
    select s
Lambda:
    Students.Select( s => s) 



4、 
查询Score表中成绩在60到80之间的所有记录。
select * 
from score where degree between 60 and 80
Linq:
    from s in Scores
    where s.DEGREE >= 
60 && s.DEGREE < 80
    select s
Lambda:
    Scores.Where( 
        s => 
(
                s.DEGREE >= 60 && s.DEGREE < 80 

             )
    )


 


5、 
查询Score表中成绩为85,86或88的记录。
select * 
from score where degree in (85,86,88)
Linq:
In
    from s in Scores
    where 
(
            new decimal[]{85,86,88}
          
).Contains(s.DEGREE)
    select s
Lambda:
    Scores.Where( s => new Decimal[] 
{85,86,88}.Contains(s.DEGREE))
Not 
in
    from s in Scores
    where !(
            new 
decimal[]{85,86,88}
          ).Contains(s.DEGREE)
    select 
s
Lambda:
    Scores.Where( s => 
!(new Decimal[]{85,86,88}.Contains(s.DEGREE)))


    
Any()应用:双表进行Any时,必须是主键为(String)
    CustomerDemographics 
CustomerTypeID(String)
    CustomerCustomerDemos (CustomerID 
CustomerTypeID) (String)
    一个主键与二个主建进行Any(或者是一对一关键进行Any)
    不可,以二个主键于与一个主键进行Any
    
    from e in 
CustomerDemographics
    where !e.CustomerCustomerDemos.Any()
    select 
e
    
    from c in Categories
    where !c.Products.Any()
    
select c


 


6、 
查询Student表中"95031"班或性别为"女"的同学记录。
select * 
from student where class =\'95031\' or ssex= N\'女\'
Linq:
    
from s in Students
    where s.CLASS == "95031" 
       || s.CLASS == 
"女"
    select s
Lambda:
    
Students.Where(s => ( s.CLASS == "95031" || s.CLASS == "女")) 



7、 
以Class降序查询Student表的所有记录。
select * 
from student order by Class DESC
Linq:
    from s in Students
    orderby s.CLASS 
descending
    select s
Lambda:
    
Students.OrderByDescending(s => s.CLASS)


 


8、 
以Cno升序、Degree降序查询Score表的所有记录。
select * 
from score order by Cno ASC,Degree DESC
Linq:(这里Cno ASC在linq中要写在最外面)
    from s in Scores
    orderby 
s.DEGREE descending
    orderby s.CNO ascending 
    select 
s
Lambda:
    
Scores.OrderByDescending( s => s.DEGREE)
          .OrderBy( s => 
s.CNO)



9、 
查询"95031"班的学生人数。
select 
count(*) from student where class = \'95031\'
Linq:
    (    from s in Students
        where 
s.CLASS == "95031"
        select s
    ).Count()
Lambda:
    Students.Where( s => s.CLASS == "95031" 
)
                .Select( s => s)
                    .Count() 


 


10、查询Score表中的最高分的学生学号和课程号。
select 
distinct s.Sno,c.Cno from student as s,course as c ,score as sc 
where 
s.sno=(select sno from score where degree = (select max(degree) from
score))
and c.cno = (select cno from score where degree = (select max(degree) 
from score))
Linq:
    (
        
from s in Students
        from c in Courses
        from sc in 
Scores
        let maxDegree = (from sss in Scores
                        
select sss.DEGREE
                        ).Max()
        let sno = (from 
ss in Scores
                where ss.DEGREE == maxDegree
                
select ss.SNO).Single().ToString()
        let cno = (from ssss in 
Scores
                where ssss.DEGREE == maxDegree
                
select ssss.CNO).Single().ToString()
        where s.SNO == sno && 
c.CNO == cno
        select new {
            s.SNO,
            
c.CNO
        }
    ).Distinct()
操作时问题?执行时报错: where s.SNO == sno(这行报出来的) 运算符"=="无法应用于"string"和"System.Linq.IQueryable<string>"类型的操作数
解决:
原:let 
sno = (from ss in Scores
                where ss.DEGREE == 
maxDegree
                select 
ss.SNO).ToString()
Queryable().Single()返回序列的唯一元素;如果该序列并非恰好包含一个元素,则会引发异常。 
解:let 
sno = (from ss in Scores
                where ss.DEGREE == 
maxDegree
                select 
ss.SNO).Single().ToString()
 


11、查询\'3-105\'号课程的平均分。
select 
avg(degree) from score where cno = \'3-105\'
Linq:
    (
        from s in Scores
        
where s.CNO == "3-105"
        select s.DEGREE
    
).Average()
Lambda:
    Scores.Where( 
s => s.CNO == "3-105")
            .Select( s => 
s.DEGREE)
                .Average()



12、查询Score表中至少有5名学生选修的并以3开头的课程的平均分数。
select 
avg(degree) from score where cno like \'3%\' group by Cno having 
count(*)>=5
Linq:
        from s in 
Scores
        where s.CNO.StartsWith("3")
        group s by 
s.CNO
        into cc
        where cc.Count() >= 5
        select 
cc.Average( c => c.DEGREE)
Lambda:
    Scores.Where( s => 
s.CNO.StartsWith("3") )
            .GroupBy( s => s.CNO 
)
              .Where( cc => ( cc.Count() >= 5) )
                
.Select( cc => cc.Average( c => c.DEGREE) )
Linq: SqlMethod
like也可以这样写:
    s.CNO.StartsWith("3") 
or SqlMethods.Like(s.CNO,"%3")


 


13、查询最低分大于70,最高分小于90的Sno列。
select sno 
from score group by sno having min(degree) > 70 and max(degree) < 
90
Linq:
    from s in Scores
    
group s by s.SNO
    into ss
    where ss.Min(cc => cc.DEGREE) > 70 
&& ss.Max( cc => cc.DEGREE) < 90
    select new
    
{
        sno = ss.Key
    }
Lambda:
    Scores.GroupBy (s => 
s.SNO)
               .Where (ss => ((ss.Min (cc => cc.DEGREE) > 70) 
&& (ss.Max (cc => cc.DEGREE) < 90)))
                   .Select 
( ss => new {
                                        sno = 
ss.Key
                                     })


 


14、查询所有学生的Sname、Cno和Degree列。
select 
s.sname,sc.cno,sc.degree from student as s,score as sc where s.sno =
sc.sno
Linq:
    from s in 
Students
    join sc in Scores
    on s.SNO equals sc.SNO
    select 
new
    {
        s.SNAME,
        sc.CNO,
        sc.DEGREE
    
}
Lambda:
    Students.Join(Scores, s 
=> s.SNO,
                          sc => sc.SNO, 

                          (s,sc) => 
new{
                                            SNAME = 
s.SNAME,
                                            CNO = 
sc.CNO,
                                            DEGREE = 
sc.DEGREE
                                          })


 


15、查询所有学生的Sno、Cname和Degree列。
select 
sc.sno,c.cname,sc.degree from course as c,score as sc where c.cno = 
sc.cno
Linq:
    from c in 
Courses
    join sc in Scores
    on c.CNO equals sc.CNO
    select 
new
    {
        sc.SNO,c.CNAME,sc.DEGREE
    }
Lambda:
    Courses.Join ( Scores, c => c.CNO, 

                             sc => sc.CNO, 

                             (c, sc) => new  

                                        
{
                                            SNO = sc.SNO, 

                                            CNAME = c.CNAME, 

                                            DEGREE = 
sc.DEGREE
                                        })


 


16、查询所有学生的Sname、Cname和Degree列。
select 
s.sname,c.cname,sc.degree from student as s,course as c,score as sc where s.sno 
= sc.sno and c.cno = sc.cno
Linq:
    
from s in Students
    from c in Courses
    from sc in Scores
    
where s.SNO == sc.SNO && c.CNO == sc.CNO
    select new { 
s.SNAME,c.CNAME,sc.DEGREE }

 

以上是关于linq lanbda表达式的用法的主要内容,如果未能解决你的问题,请参考以下文章

初识委托,泛型委托,表达式树,Lanbda

Java8之lanbda表达式学习

Lambda--持续学习中

jdk8-lanbda方法引用和构造引用

LINQ 表达式返回属性值?

Python lambda函数