openurl 跳转

Posted 2020-07-29 rexzhao

1.拨打电话：

 

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel://68979"]]; //直接拨打
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"telprompt://68979"]]; //弹出确订提示

2.调用Safari打开网址:

 

 

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.baidu.com"]];

 

3.发送邮件：

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"mailto://[email protected]"]];

4.发送短信：

 

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"sms://68979"]];

 

5.打开Appstore:

 

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"itms-apps://itunes.apple.com/us/app/id%@", AppID]]];

 

 

ios 8開始支持跳转到应用的设置页：

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];