5位数判断

Posted 2022-08-24 dbda

//给出一个不超过5位的正整数，要求：

//1.求出它是几位数 2.分别打印出每一位数字 3.按逆序打印出各位数字

let readline = require("readline-sync");

console.log("请输入数字")

let num = parseInt(readline.question(""));

if (num > 99999 || num < 0)

console.log("你输入的数字不符合要求");

else if (parseInt(num / 10000) > 0)

let wan = parseInt(num / 10000);

let qian = parseInt(num % 10000 / 1000);

let bai = parseInt(num % 1000 / 100);

let shi = parseInt(num % 100 / 10);

let ge = parseInt(num % 10);

console.log("这是一个5位数");

console.log("数字为：", num);

console.log("万位：", wan, "千位", qian, "百位", bai, "十位", shi, "个位", ge);

let newNum = ge * 10000 + shi * 1000 + bai * 100 + qian * 10 + wan

console.log("逆序输出为：", newNum);

else if (parseInt(num / 1000) > 0)

let qian = parseInt(num % 10000 / 1000);

let bai = parseInt(num % 1000 / 100);

let shi = parseInt(num % 100 / 10);

let ge = parseInt(num % 10);

console.log("这是一个4位数");

console.log("数字为：", num);

console.log("千位", qian, "百位", bai, "十位", shi, "个位", ge);

let newNum = ge * 1000 + shi * 100 + bai * 10 + qian;

console.log("逆序输出为：", newNum);

else if (parseInt(num / 100) > 0)

let bai = parseInt(num % 1000 / 100);

let shi = parseInt(num % 100 / 10);

let ge = parseInt(num % 10);

console.log("这是一个3位数");

console.log("数字为：", num);

console.log("百位", bai, "十位", shi, "个位", ge);

let newNum = ge * 100 + shi * 10 + bai;

console.log("逆序输出为：", newNum);

else if (parseInt(num / 10) > 0)

let shi = parseInt(num % 100 / 10);

let ge = parseInt(num % 10);

console.log("这是一个2位数");

console.log("数字为：", num);

console.log("十位", shi, "个位", ge);

let newNum = ge * 10 + shi;

console.log("逆序输出为：", newNum);

else

console.log("这是一个1位数");

console.log("数字为：", num);

console.log("个位", num);

console.log("逆序输出为：", num);