Poj1426 DFS模板题
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Find The Multiple
Time Limit: 1000MS | Memory Limit: 10000K | |||
Total Submissions: 51502 | Accepted: 21541 | Special Judge |
题目链接:http://poj.org/problem?id=1426
Description
Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.
Input
The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.
Output
For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.
Sample Input
2 6 19 0
Sample Output
10 100100100100100100 111111111111111111
题意:输入一个数n,求只有0和1的数并且还是n的倍数的数是多少
思路:直接dfs搜,暴力搜
#include <iostream> using namespace std; typedef unsigned long long ULL; int n; bool flag = false; void DFS(int step, ULL t) if(step > 19 || flag) return; if (t % n == 0) cout << t << endl; flag = true; return; DFS(step + 1, 10 * t); DFS(step + 1, 10 * t + 1); int main() while (cin >> n) if (!n) return 0; flag = false; DFS(1, 1); return 0;
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