mysql查询今天昨天本周本月上一月 今年数据

Posted 2022-08-20 testcase

mysql数据库中的关于查询日期的一些操作如下：

--今天

select * from 表名 where to_days(时间字段名) = to_days(now());

--昨天

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1

--本周

SELECT * FROM 表名 WHERE YEARWEEK( date_format( 时间字段名,‘%Y-%m-%d‘ ) ) = YEARWEEK( now() ) ;

--本月

SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, ‘%Y%m‘ ) = DATE_FORMAT( CURDATE( ) ,‘%Y%m‘ )

--上一个月

SELECT * FROM 表名 WHERE PERIOD_DIFF(date_format(now(),‘%Y%m‘),date_format(时间字段名,‘%Y%m‘) =1

--本年

SELECT * FROM 表名 WHERE YEAR( 时间字段名 ) = YEAR( NOW( ) )


--上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m‘ ) , date_format( 时间字段名, ‘%Y%m‘ ) ) =1

 

--查询本季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
--查询上季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
--查询本年数据
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
--查询上年数据
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

 


--查询当前这周的数据 
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,‘%Y-%m-%d‘)) = YEARWEEK(now());

--查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,‘%Y-%m-%d‘)) = YEARWEEK(now())-1;

--查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,‘%Y-%m‘)=date_format(now(),‘%Y-%m‘)

--查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

--查询上个月的数据
select name,submittime from enterprise where date_format(submittime,‘%Y-%m‘)=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),‘%Y-%m‘)

select * from ` user ` where DATE_FORMAT(pudate, ‘ %Y%m ‘ ) = DATE_FORMAT(CURDATE(), ‘ %Y%m ‘ ) ;

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,‘%y-%m-%d‘)) = WEEKOFYEAR(now())

select * 
from user 
where MONTH (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH (now())

select * 
from [ user ] 
where YEAR (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH (now())

select * 
from [ user ] 
where pudate between 上月最后一天
and 下月第一天

where date(regdate) = curdate();

select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())

SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30

转自：https://www.cnblogs.com/shuilangyizu/p/8805384.html